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3 years ago

Tell whether the equation has one, zero, or infinitely many solutions. 8(x-4) + 19 = 8x - 13

Mathematics

1 answer:

Alex3 years ago

8 0

Answer:

This problem has infinite many solutions.

Step-by-step explanation:

8(x−4)+19=8x−13

Step 1: Simplify both sides of the equation.

8(x−4)+19=8x−13

(8)(x)+(8)(−4)+19=8x+−13(Distribute)

8x+−32+19=8x+−13

(8x)+(−32+19)=8x−13(Combine Like Terms)

8x+−13=8x−13

8x−13=8x−13

Step 2: Subtract 8x from both sides.

8x−13−8x=8x−13−8x

−13=−13

Step 3: Add 13 to both sides.

−13+13=−13+13

0=0

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Create a two step equation that results in the answer being 5.

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2x + 3 = 13

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Help with this question ASAP!

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Step-by-step explanation:

Given the ball is initially projected upwards with a velocity of 64ft per sec and we are required to find the time at which it reaches the ground .There are many approaches to solve this problem we will follow this one:

It is also known as the time of flight for the ball which can be found by doubling the time taken for the ball to reach to its maximum height or the point where velocity is zero.

Now $h(t)=-16\times t^{2} +v_{0} \times t+h_{0}$

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3 years ago

50 points + brainlest if you answer correctly

Mumz [18]

Answer:

5 is the value which makes the equation true .

Step-by-step explanation:

In this question we have provided an equation that is 9 ( 3x - 16 ) + 15 = 6x - 24 . And we are asked to write the steps to solve the equation with explanation  and to find the value of X .

Solution : -

$\longmapsto \quad \: 9(3x - 16) + 15 = 6x - 24$

Step 1 : Solving parenthesis on left side using distributive property which means multiplying 9 with 3x as well as -16 :

$\longmapsto \quad \:27x - \bold{144 }+ \bold{15 }= 6x - 24$

Step 2 : Solving like terms on left side that are -144 and 15 :

$\longmapsto \quad \:27x -129 = 6x - 24$

Step 3 : Adding 129 on both sides :

$\longmapsto \quad \:27x - \cancel{129} - \cancel{129} = 6x \bold{ - 24 } + \bold{129}$

Now on cancelling -129 with 129 on left side and solving the terms that are -24 and 129 on right side , We get :

$\longmapsto \quad \:27x = 6x + 105$

Step 4 : Subtracting with 6x on both sides :

$\longmapsto \quad \: \bold{27x} - \bold{6x} = \cancel{6x} +105 - \cancel{ 6x}$

On calculating further, We get :

$\longmapsto \quad \:21x = 105$

Step 5 : Now we are Dividing with 21 on both sides so that we can isolate the variable that is x :

$\longmapsto \quad \: \dfrac{ \cancel{21}x}{ \cancel{21}} = \dfrac{105}{ 21}$

Now , by cancelling 21 with 21 on left side , We get :

$\longmapsto \quad \:x = \cancel{\dfrac{105}{21}}$

Step 6 : Now our final step is to simplify the value of x that is 105/21 . We know that 21 × 5 is equal to 105 . So :

$\longmapsto \quad \: \purple{\underline{\boxed{\frak{ x = 5 }}}}$

Henceforth , value of x is 5

Verifying : -

Now we are verifying our answer by substituting value of x in the given equation . So ,

9 ( 3x - 16 ) + 15 = 6x - 24

9 [ 3 ( 5 ) - 16 ] + 15 = 6 ( 5 ) - 24

9 ( 15 - 16 ) + 15 = 30 - 24

9 ( -1 ) + 15 = 6

-9 + 15 = 6

6 = 6

L.H.S = R.H.S

Hence , Verified .

Therefore, our value for x is correct that means it'll makes the equation true .

<h2>#Keep Learning</h2>

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2 years ago

Find the equation (in standard form) whose center is (5, -3) and goes through (2, 5).

yanalaym [24]

We can write this as

(x - 5)^2 + (y + 3)^2 = r^2

where r = radius

Plugging in the point (2,5) we have

(2-5)^2 + (5+3)^2 = r^2
r^2 = 9 + 64 = 73
so the required equation is

(x - 5)^2 + (y + 3)^2 = 73

3 0

3 years ago