Remember
we can do anything to an equation as long as we do it to both sides
try to isolate the variable
you have 2 types
x+b=c
x/b=c
fior the first type, minus b from both sides to get
x=c-b
for the second, multiply both sides by b to get rid of the fraction to get
x=cb
also remember that -x times -1=x
b.add 25 to both sides
-a=20
multiply -1
a=-20
c.
-t/8=-4
multiply both sides by 8
-t=-32
mutiply -1
t=32
d. -n/-5=-30
mulitply both sides by -5
-n=150
multiply both sides by -1
n=-150
e. multiply both sides by 12
-l=144
multiply b y-1
l=-144
There are 4 red slices out of 9 total. So there are 9-4 = 5 slices that are not red. The odds in favor of landing on red is 4:5
We basically write the number of ways to get what we want (4), followed by a colon, then the second number is the number of ways to get what we don't want (anything but red; 5 ways)
So that's why the answer is 4:5
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Side Note -- If we want the odds against, we simply flip the ratio. The odds against would be 5:4 because there are 5 ways to lose and 4 ways to win. This is assuming that landing on red means you win.
Answer:
I want to say C
Figure jkl is simular to fugure jkl :)
1,2,3
all would give negative results
Answer:
P(success at first attempt) = 0.1353
Step-by-step explanation:
This question follows poisson distribution. Thus, the formula is;
P(k) = (e^(-G) × (G)k)/k!
where;
G is number of frames generated in one frame transmission time(or frame slot time)
Let's find G.
To do this, we need to find number of frames generated in 1 slot time which is given as 50 ms.
Now, in 1000 ms, the number of frames generated = 50
Thus; number of frames generated in 50 ms is;
G = (50/1000) × 50
G = 2.5
To find the chance of success on the first attempt will be given by;
P(success at first attempt) = P(0) = e^(-G) = e^(-2) = 0.1353
