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lbvjy [14]
3 years ago
5

Write the expression using a single exponent 2^2•2^8

Mathematics
1 answer:
kondor19780726 [428]3 years ago
5 0

I think it’s C. 4^16,

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What is -2 2/3 • -4 3/7
Tanya [424]

Answer:

11 17/21

Step-by-step explanation:

5 0
3 years ago
Approximate: log5 4/7
Evgesh-ka [11]
   Properties of Logs

logb(x/y) = log<span>bx</span> - log<span>by</span>.

therefore

log5 (4/7)= log5 (4)- log5 (7)

<span>Solve log 5 (4) and log 5 (7)  with the base change of the logarithm</span>

<span>log 5 4 = log 4 / log 5 </span>

 Use the calculator: 

<span> <span>log 5 4 =0.8613531161 </span></span>

 log 5 7 = log 7 / log 5 

<span>log 5 7 =1.2090619551</span>

<span>log5 (4/7)= log5 (4)- log5 (7)=-0.347708839</span>

6 0
3 years ago
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If f(x)=2−x12 and g(x)=x2−9, what is the domain of g(x)÷f(x)?
Keith_Richards [23]
\bf \begin{cases}&#10;f(x)=2-x^{12}\\&#10;g(x)=x^2-9\\&#10;g(x)\div f(x)=\frac{g(x)}{f(x)}&#10;\end{cases}\implies \cfrac{x^2-9}{2-x^{12}}

now, for a rational expression, the domain, or "values that x can safely take", applies to the denominator NOT becoming 0, because if the denominator is 0, then the rational turns to undefined.

now, what value of "x" makes this denominator turn to 0, let's check by setting it to 0 then.

\bf 2-x^{12}=0\implies 2=x^{12}\implies \pm\sqrt[12]{2}=x\\\\&#10;-------------------------------\\\\&#10;\cfrac{x^2-9}{2-x^{12}}\qquad \boxed{x=\pm \sqrt[12]{2}}\qquad \cfrac{x^2-9}{2-(\pm\sqrt[12]{2})^{12}}\implies \cfrac{x^2-9}{2-\boxed{2}}\implies \stackrel{und efined}{\cfrac{x^2-9}{0}}

so, the domain is all real numbers EXCEPT that one.
4 0
3 years ago
I need help what is the answer
-Dominant- [34]
Distribute first, combine the like terms and then add all of the sides up.
8 0
3 years ago
A hockey player passes a puck to his teammate by bouncing it off a wall. The angles formed when the puck hits the wall and bounc
UkoKoshka [18]
X     8-- = --12    9
96 = 9x
x = 10.67 ft.
7 0
3 years ago
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