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sp2606 [1]
3 years ago
13

Two equations are given below:

Mathematics
1 answer:
Evgesh-ka [11]3 years ago
6 0

The solution to the set of equations is (0,2).

Reasoning:

m + 4n = 8 -> 0 + 4(2) = 8

m = n - 2 -> 0 = 2 - 2

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Workout to the simplest:<br><img src="https://tex.z-dn.net/?f=%20%20%5Cint%20%5C%3A%20%20%7Bx%7D%5E%7B2%7D%20%20ln%28%20%7Bx%7D%
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Step-by-step explanation:

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Given a function <img src="https://tex.z-dn.net/?f=f%28x%29%3D3x%5E4-5x%5E2%2B2x-3" id="TexFormula1" title="f(x)=3x^4-5x^2+2x-3"
Levart [38]

Answer:

\huge\boxed{f(-1) = -7}

Step-by-step explanation:

In order to solve for this function, we need to substitute in our value of x inside to find f(x). Since we are trying to evalue f(-1), we will substitute -1 in as x to our equation.

f(-1) = 3(-1)^4 - 5(-1)^2 + 2(-1) - 3

Now we can solve for the function by multiplying/subtracting/adding our known values.

Starting with the first term to the last term:

  • 3(-1)^4 = 3

<u><em>WAIT</em></u><em>!</em><em> How is this possible? </em>-1^4 = -1 (according to my calculator), and 3 \cdot -1 = -3, not 3!

It's important to note that taking a power of a negative number and multiplying a negative number are two different things. Let's use -2^2 as an example.

What your calculator did was follow BEMDAS since it wasn't explicitly told not to.

BEMDAS:

- Brackets

- Exponents

- Multiplication/Division

- Addition/Subtraction

Examining the equation, your calculator used this rule properly. Note that exponents come over multiplication.

So rather than  being <em>"-2 squared"</em> - it's <em>"the negative of of 2 squared."</em>

Tying this back into our problem, the squared method would only be true if it looks like -1^4. However, since we're substituting in -1, it looks like (-1)^4, so the expression reads out as "<u><em>-1 to the fourth.</em></u>"

MULTIPLYING -1 by itself 4 times results in -1\cdot-1\cdot-1\cdot-1=1.

Applying this logic to our original term, 3(-1)^4:

  • 3(-1\cdot-1\cdot-1\cdot-1)
  • 3(1)
  • 3

Therefore, our first term is 3.

Let's move on to our second and third terms.

Second term: -5x^2

  • -5(-1)^2

Applying the same logic from our first term:

  • -5(-1 \cdot -1)
  • -5(1)
  • -5

Third term: 2x

  • 2(-1) = -2

-3 is just -3, no influence of x.

Combining our terms, we have 3-5-2-3.

This comes out to be -7, hence, the value of f(-1) for our function f(x)=3x^4-5x^2+2x-3 is <u>-7</u>.

Hope this helped!

4 0
3 years ago
Read 2 more answers
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