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iogann1982 [59]
3 years ago
10

Write the equation of the line given points (-4,6) and (-8,10)

Mathematics
1 answer:
Advocard [28]3 years ago
6 0

Answer:

the equation of the line in slope-intercept form is: y=-x+2

Step-by-step explanation:

First start by finding the slope of the segment that joins those two points using the general formula for the slope of the segments between two points (x_1,y_1) and (x_2,y_2) on the plane:

Slope=\frac{y_2-y_1}{x_2-x_1}

Then for our case, calling (-4, 6) = (x_1,y_1) and (-8, 10) = (x_2,y_2), we have:

Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{10-6}{-8-(-4)}\\Slope=\frac{4}{-8+4}\\Slope=\frac{4}{-4}\\Slope= -1

Now, knowing this, we can find the equation of the line by using the "point-slope" form of a line [of slope "m" and going through the point (x_0,y_0) that tells us:

y-y_0=m(x-x_0)

We will be then using the found slope (-1) and for example one of the given points: (-4 , 6), thus:

y-y_0=m(x-x_0)\\y-6=-1(x-(-4))\\y-6=-1(x+4)\\y-6=-x-4\\y=-x-4+6\\y=-x+2

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