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bija089 [108]
2 years ago
14

What is the probability of rolling a number greater than or equal to 9 with the sum of two dice, given that at least one of the

dice must show a 6? A. 4/11 B. 7/11 C. 2/11 or D. 9/11
Mathematics
1 answer:
olga55 [171]2 years ago
6 0
Conditional probablility P(A/B) = P(A and B) / P(B). Here, A is sum of two dice being greater than or equal to 9 and B is at least one of the dice showing 6. Number of ways two dice faces can sum up to 9 = (3, 6), (4, 5), (4, 6), (5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 10 ways. Number of ways that at least one of the dice must show 6 = (1, 6), (2, 6), (3, 6), (4, 6), (5, 6), (6, 6), (6, 5), (6, 4), (6, 3), (6, 2), (6, 1) = 11 ways. Number of ways of rolling a number greater than or equal to 9 and at least one of the dice showing 6 = (3, 6), (4, 6), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 7 ways. Probability of rolling a number greater than or equal to 9 given that at least one of the dice must show a 6 = 7 / 11
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SIZIF [17.4K]
0.10d + 0.25q = 3.55
q = d + 3

0.10d + 0.25(d + 3) = 3.55
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