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3 years ago

The lengths and widths of two rectangles are proportional. One

1 answer:

5 0

The width of the rectangle would be 6 times the first rectangle and the length would be 8 times the first rectangle.

Explanation:

Given:

Two rectangles are proportional.

Length and width of 1 rectangle = 6 : 8

Dimensions of the other rectangle = ?

Let length and width of the other rectangle be x : y

According to the question:

$\frac{6}{8} :\frac{x}{y}$

$\frac{6}{8} X \frac{y}{x}$

So, the width of the rectangle would be 6 times the first rectangle and the length would be 8 times the first rectangle.

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3 years ago

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olya-2409 [2.1K]

The problem is confusing because the words (and question marks) are not consistently used. Let's do this:

... (cooler price) + (tax on the cooler) = (total bill)

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Using the distributive property, we can factor out (cooler price) to get ...

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Adding the numbers together, we have

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There are two question marks in the addition problem, and each gets a different number. I can't tell from the portion of the picture here what the expected answer is. (I suspect it may be 106%.) I can tell you ...

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== == == == == == == ==

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Answer:

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Step-by-step explanation:

The square in the middle has a length and width of 3, so multiply. 9.

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So base*height is 6. Divide that by 2 or multiply by 1/2.

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Add 12 and 9 together, and you get:

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3 years ago