The width of the rectangle would be 6 times the first rectangle and the length would be 8 times the first rectangle.
<u>Explanation:</u>
Given:
Two rectangles are proportional.
Length and width of 1 rectangle = 6 : 8
Dimensions of the other rectangle = ?
Let length and width of the other rectangle be x : y
According to the question:
So, the width of the rectangle would be 6 times the first rectangle and the length would be 8 times the first rectangle.
Answer:
i believe the answer is 3^2(-2)^6/ 5^4
Step-by-step explanation: