Question

X^2-6x+4=0 Please explain how to do quadratic formula with this problem.

Answer 1

$x^{2} - 6x + 4 = 0$
$\frac{-(-6) \± \sqrt{-(-6)^{2} - 4(1)(4)}}{2(1)}$
$\frac{6 \± \sqrt{36 - 16}}{2}$
$\frac{6 \± \sqrt{20}}{2}$
$\frac{6 \± 2\sqrt{5}}{2}$
$3 \± \sqrt{5}$
$3 + \sqrt{5}$    $or$    $3 - \sqrt{5}$