(not sure )
my method
let projection of b onto line dq be M
BM is 2r
then let the remaining angle ( right) be K
in triangle BMK ,
MK = 29-5-r
By Pyth. theorem ,
23^2 = (2r)^2+(29-5-r)^2
529=4r^2+576-48r+r^2
5r^2-48r+47=0
r = 8.493237063 or 1.106762937(rejected)
We're going to use the equation given but let's first make sure we understand what the equation IS saying:
Area of a kite= [(1st diagonal) × (2nd diagonal)]/2
Now, let's find the 2 diagonals. In the case of kite shapes one of the diagonals is the line that goes from W to Y and the other is the line going from X to Z. In a kite they will always cross (no matter their lengths).
Now that we know the diagonals we can add the lengths that are given for each line to know what to multiply.
Line W to Y: 20+12= 32
Line X to Z: 12+12= 24
Now let's plug these numbers into the equation (it doesn't matter the order of the diagonals because we're just gonna be multiplying them either way!)
So...
(32×24)/2= 384 units squared (because it is area)
Answer:
there both cercles
Step-by-step explanation:
Answer:
{x,y} = {19/12,5/6}
Step-by-step explanation:
