Answer:
what does it pass through
V=hpir^2
tricky, they didn't give us radius
they just gave circiufmerece
c=2pir
25.12=2pir
divide by 2 both sides
12.56=pir
divide by 3.14 both sides
4=r
subsitutet
v=hpir^2
v=66pi4^2
v=66pi16
v=1056pi
v=3315.84 cubic inches
Answer:
a. 24
b. 2
c. 0.0833 = 8.33%
Step-by-step explanation:
a.
The first "slot" of person to arrive has 4 possibilities, then the second "slot" will have 3 possibilities, as one has already arrived, then the third "slot" has 2 possibilities, and the fourth "slot" has just 1 possibility.
So, multiplying all these combinations, we have 4*3*2*1 = 24 possible ways they can arrive
b.
If the first and the last person are already "locked", we just have possibilities for the second and third person. The second will have 2 possibilities (Sergio or Tyrone), and the third will have only 1 (the person that wasn't the second between Sergio and Tyrone). So, the number of possibilities is 2*1 = 2
c.
If we have 2 cases where Dawn is first and Jim is last, from a total of 24 possible cases, the probability is 2/24 = 1/12 = 0.0833 = 8.33%
Answer: A
Step-by-step explanation:
<u>Part 1) </u>To find the measure of ∠A in ∆ABC, use
we know that
In the triangle ABC
Applying the law of sines
in this problem we have
therefore
<u>the answer Part 1) is</u>
Law of Sines
<u>Part 2) </u>To find the length of side HI in ∆HIG, use
we know that
In the triangle HIG
Applying the law of cosines
In this problem we have
g=HI
G=angle Beta
substitute
therefore
<u>the answer Part 2) is</u>
Law of Cosines
