Slope = (y2-y1)/(x2-x1)
(3+1)/(2-0) = 4/2 = 2
The slope is 2
y=4^x −1
x intercept is the point when y = 0, so you sub in 0 for y:
0 = 4^x - 1
4^x = 1
Any number excluding 0 that is raised to the the exponent 0 always equals 1, 0^0 is undetermined.
x = 0
x intercept = (0,0)
If the x intercept is at the origin (0,0) than the y intercept is also (0,0)
s is the only line that passes through (0,0)
Complete the square of y^2 + 10y to answer this question.
x=y^2 + 10y + 22 becomes x = <em>y^2 + 10y + 100</em> - 100 + 22, or
x = (y+10)^2 - 78
Comparing this result to the generic form x = a(y-k)^2 + h, we see that
h = -78 and k = -10.
Then the vertex of this parabola is at (-78, -10).
Answer:
148
Step-by-step explanation: