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Liula [17]
3 years ago
15

Use the graphs of the transformed toolkit functions to write a formula for each of the resulting functions.

Mathematics
1 answer:
dimaraw [331]3 years ago
6 0

Answer:

y=-(x+1)^2+2.

Step-by-step explanation:

This is a parabola so it's parent is y=x^2.

Let's described what happened to get from the parent to this.

The graph has been reflected so we will have y=-x^2.

The graph has been moved left 1 and up 2 so this gives us:

y=-(x-(-1))^2+2.

Simplifying this gives us y=-(x+1)^2+2.

Let's see if a few points we can identify can help confirm or convince you.

Some points I see that cross nicely are:

(-3,-2)

(-2,1)

(-1,2)

(0,1)

(1,-2)

Let's check them and see.

y=-(x+1)^2+2 with (x,y)=(-3,-2):

-2=-(-3+1)^2+2

-2=-(-2)^2+2

-2=-4+2

-2=-2 is true so (-3,-2) does satisfy y=-(x+1)^2+2.

y=-(x+1)^2+2 with (x,y)=(-2,1):

1=-(-2+1)^2+2

1=-(-1)^2+2

1=-1+2

1=1 is true so (-2,1) does satisfy y=-(x+1)^2+2.

y=-(x+1)^2+2 with (x,y)=(-1,2):

2=-(-1+1)^2+2

2=-(0)^2+2

2=0+2

2=2 is true so (-1,2) does satisfy y=-(x+1)^2+2.

y=-(x+1)^2+2 with (x,y)=(0,1):

1=-(0+1)^2+2

1=-(1)^2+2

1=-1+2

1=-1 is true so (0,1) does satisfy y=-(x+1)^2+2.

y=-(x+1)^2+2 with (x,y)=(1,-2):

-2=-(1+1)^2+2

-2=-(2)^2+2

-2=-4+2

-2=-2 is true so (1,-2) does satisfy y=-(x+1)^2+2.

All the mentioned points satisfied our equation:

y=-(x+1)^2+2

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4(x+7) becomes 4x+28 you multipli the 4 in parentheses ans 2(x+7) becomes 2x+14

4x+28=2x+14 you move the x termes to the left and other numbers to the right look:

4x-2x=14-28 when you change the sides always change the sign +or-
2x=-14
2x/2=-14/2
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Answer:

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PLZ
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Answer:

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Step-by-step explanation:

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An electrolyte solution has an average current density of 1 ampere per square decimeter (A/dm^2). What is the current density of
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GIVING BRAINLIEST WHOEVER ANSWER THIS CORRECT THANK U.
Sonja [21]

Answer:

The coordinates of Y' and Z' are, respectively Y'(6,-1) Z'(-2,0)

Step-by-step explanation:

Translations

A given point A(x,y) when translated by the rule (h,k) maps to A'(x+h,y+k).

We are given the point X(3,-2) and its image at X'(2,-4). The rule for the translation used is:

(h,k)=(2,-4)-(3,-2)=(2-3,-4+2)=(-1,-2)

If we apply the same translation to the point Y(7,1) we get the image Y'(7-1,1-2)=Y'(6,-1).

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The coordinates of Y' and Z' are, respectively Y'(6,-1) Z'(-2,0)

it's a example from another eqaqthion

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