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Alja [10]
3 years ago
10

Write a small program basic c++, that defines a negative integer (between ‐1 and ‐255), converts it to a positive value and then

displays it on the console window.
Computers and Technology
1 answer:
ANEK [815]3 years ago
4 0

Answer:

#include <iostream>

using namespace std;

int main() {

int a=-156;//negative integer between -1 and -255.

a*=-1;//multiplying a to -1 so that it can become positive.

cout<<a;//printing a.

return 0;

}

Explanation:

The above written program is in C++ and in the program an integer a is defined with a negative value in the program it is -156.Then to convert it to positive integer we have to multiply a to -1 after that printing the value of a on the screen.

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dolphi86 [110]

Answer:

The regular bottle holds 9 fluid ounces less than the family size bottle.

Explanation:

The family size bottle of sunscreen holds 12 fluid ounces

The regular bottle holds 75 percent less

75 percent of 12 = (75/100) X 12 =0.75 X 12 =9

Since the regular bottle holds 75% less, it holds 9 fluid ounces fewer fluid than the family size bottle of sunscreen.

NOTE: The regular size holds three(3) fluid ounces of sunscreen.

6 0
3 years ago
File Sales.java contains a Java program that prompts for and reads in the sales for each of 5 salespeople in a company. It then
myrzilka [38]

Answer:

import java.util.Scanner;

public class Sales

{

public static void main(String[] args) {

   

    int sum;

    Scanner input = new Scanner(System.in);

   

    System.out.print("Enter number of salespeople: ");

    int salespeople = input.nextInt();

    int[] sales = new int[salespeople];

       

    for (int i=0; i<sales.length; i++)

    {

     System.out.print("Enter sales for salesperson " + (i+1) + ": ");

     sales[i] = input.nextInt();

    }

    System.out.println("\nSalesperson   Sales");

    System.out.println("--------------------");

    sum = 0;

       int maxSale = sales[0];

       int minSale  = sales[0];

       int minId=1;

       int maxId=1;

    for (int i=0; i<sales.length; i++)

    {

               System.out.println("     " + (i+1) + "         " + sales[i]);

 sum += sales[i];

  if(maxSale < sales[i])

           {

               maxSale = sales[i];

               maxId = i+1;

           }

           if(minSale > sales[i])

           {

               minSale = sales[i];

               minId = i+1;

           }

   }

System.out.println("Total sales: " + sum);

       System.out.println("The average sale is: " + sum / salespeople );

       System.out.println("Salesperson "+ maxId + " had the highest sale with "+ maxSale + ".");

       System.out.println("Salesperson "+ minId + " had the lowest sale with "+ minSale + ".");

       

       int amount = 0;

       int counter = 0;

       System.out.print("Enter an amount: ");

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       for (int i=0; i<sales.length; i++)

    {

     if(sales[i] > amount) {

         counter++;

         System.out.println("Salesperson "+ (i+1) + " exceeded given amount. (Number of sales: " + sales[i] +")");

     }

    }

       System.out.println("Number of salespeople exceeded given amount is: "+ counter);

}

}

Explanation:

- Ask the user for the number of salesperson

- According to entered number, create an array called sales to hold sale number for each person

- In the first for loop, assign the given sales numbers

-  In the second for loop, print all the sales people with sales, calculate the total sales. Also, find the minimum and maximum sales numbers with associated individuals.

- Print total, average, highest, and lowest sales.

- Ask user enter an amount

- In the third for loop, find the sales people who exceeded this amount.

- Print number of sales people who exceeded the amount.

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Answer:

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andrew-mc [135]

Answer:

I think its the second one

6 0
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