Answer:
Following are the program in the C++ Programming Language.
#include <iostream>
using namespace std;
//define function for swapping
void SwapValues(int* userVal1,int* userVal2){
//set integer variable to store the value
int z = *userVal1;
//interchange their value
*userVal1 = *userVal2;
//interchange their value
*userVal2 = z;
}
//define main method
int main()
{
//declare variables
int x,y;
//get input from the user
cin>>x>>y;
//Call the method to swap the values
SwapValues(&x,&y);
//print their values
cout<<x<<" "<<y;
return 0;
}
<u>Output</u>:
3 8
8 3
Explanation:
<u>Following are the description of the program</u>.
- Firstly, we define required header file and function 'SwapValues()', pass two pointer type integer variables in argument that is 'userVal1' and 'userVal2'.
- Set integer data type variable 'z' and initialize the value of 'userVal1' in it, then initialize the value of 'userVal2' in 'userVal1' and then initialize the value of 'z' in 'userVal2'.
- Finally, define the main method in which we set two integer type variables and get input from the user in it then, call and pass those variables and print it.
Answer:
Its B.change the user name.
Explanation:
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Answer:
def sum_1k(M):
s = 0
for k in range(1, M+1):
s = s + 1.0/k
return s
def test_sum_1k():
expected_value = 1.0+1.0/2+1.0/3
computed_value = sum_1k(3)
if expected_value == computed_value:
print("Test is successful")
else:
print("Test is NOT successful")
test_sum_1k()
Explanation:
It seems the hidden part is a summation (sigma) notation that goes from 1 to M with 1/k.
- Inside the <em>sum_1k(M)</em>, iterate from 1 to M and calculate-return the sum of the expression.
- Inside the <em>test_sum_1k(),</em> calculate the <em>expected_value,</em> refers to the value that is calculated by hand and <em>computed_value,</em> refers to the value that is the result of the <em>sum_1k(3). </em>Then, compare the values and print the appropriate message
- Call the <em>test_sum_1k()</em> to see the result
