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ra1l [238]
1 year ago
13

Math 6 Trimester B Apex Learning TA 5.2.4 Practice: Writing Expressions Math 6 Trimester B Points Possible 5 Practice Presalus V

alencia Morales Name Date: Tips for Success • Read the assignment carefully and make sure you answer each part of the question or questions, Check your work when you're done, . Your Assignment Todd and his friends are painting 5 equal sections of a wall. The wall is 10 feet tall, but its length is unknown Each section will be a different color, so they need to know the area of each section 10 ft Total length unknown (x) 1. Write an expression for the total area of the wall. Explain how you came up with your expression Write your answer in the space below. 2. To find the area of each section, what do you need to do to the total area? Write your answer in the space below.
Mathematics
1 answer:
Fudgin [204]1 year ago
6 0

the height of the wall is 10 ft

the area of each section is 10

NOw divide the height of the wall in equal 5 parts.

10/5 = 2 ft ( height of each section)

as an area of the section is 10

2 x l = 10

l = 10/2

l = 5 ft

so the length of each section is 5 ft

so total length of the wall is 5 x 5 = 25 square ft.

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There are 53 regular pencils in the box and some colored pencils in the box. There are a total of 84 pencils. How many colored p
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Let be "x" the number of colored pencils in the box.

According to the information given in the exercise, there are 84 pencils in the box and 53 of them are regular pencils.

Knowing this information, you can set up the following equation:

x+53=84

Finally, you have to solve for the variable "x" in order to find its value. In order to do this, you can apply the Subtraction property of equality by subtracting 53 from both sides of the equation:

\begin{gathered} x+53-(53)=84-(53) \\ x=31 \end{gathered}

The answer is: There are 31 colored pencils in the box.

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1 year ago
A fair cube has 2 blue sides, 2 red sides, and 2 green sides.
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You can also say 66%

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2 years ago
Jasmine cell phone company charges her $35 a month for phone service plus $.50 for each text message how many text messages does
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3 years ago
Suppose the weights of the Boxers at this club are Normally distributed with a mean of 166 pounds and a standard deviation of 5.
lesya [120]

Answer:

0.1994 is the required probability.      

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 166 pounds

Standard Deviation, σ = 5.3 pounds

Sample size, n = 20

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

Standard error due to sampling =

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P(sample of 20 boxers is more than 167 pounds)

P( x > 167) = P( z > \displaystyle\frac{167 - 166}{1.1851}) = P(z > 0.8438)

= 1 - P(z \leq 0.8438)

Calculation the value from standard normal z table, we have,  

P(x > 167) = 1 - 0.8006= 0.1994 = 19.94\%

0.1994 is the probability that the mean weight of a random sample of 20 boxers is more than 167 pounds

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2 years ago
Write a letter to a friend in another town invite him or her to spend Christmas holidays with you​
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Answer:

hey my friend please come over to spend the Christmas holidays with me and my family this year. If you are afraid of your dad it's ok I'll ask my mom to call him and ask him

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