Answer:
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.
Step-by-step explanation:
Statement is incorrect. Correct form is presented below:
<em>The height </em>
<em> of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation </em>
<em>, where </em>
<em> is time in seconds. After how many seconds will the ball be 84 feet above the ground. </em>
We equalize the kinematic formula to 84 feet and solve the resulting second-order polynomial by Quadratic Formula to determine the instants associated with such height:
(1)
By Quadratic Formula:
, 
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.
For a 7 sides polygon which is called heptagon or septagon
Interior angles = (7-2)*180/7 = 128.57°
Exterior angle = 180 - 128.57 = 51.43°
Central angle = 360/7 = 51.43°
The statements which are correct:
<span>3. The regular polygon ABCDEFG can be broken down into 2 isosceles trapezoids and 1 isosceles triangle
</span>
<span>5. The central angle of the polygon ABCDEFG is about 51.43° and each interior angle is about 128.57°
</span>
<span>7. The central angle ABCDEFG is the same measure of the exterior angle
</span>
Answer:
Dónde está
Step-by-step explanation:
-10-40n-8
-18-40n
2(-9-20n)
Answer:
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