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2 years ago

The ratio 21:28 in simplest form is ?!

Mathematics

2 answers:

soldier1979 [14.2K]2 years ago

7 0

21: 28

Upon further division by 7 becomes 3:4

The simplest form is 3:4

RSB [31]2 years ago

5 0

So, to find how to simplify this, you need to:
1) Find a number that can be divided by BOTH 21 and 28.
2) Divide BOTH 21 and 28 by that number.

Let's do it!
7 is the number that can be divided by BOTH 21 and 28;
21 ÷ 7 = 3
28 ÷ 7 = 4

So, the answer is:
3:4

I hope this helps! If it did, a Brainliest would be really appreciated! <3
Have a great day!

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True or false 398+9 = 400+8

defon

Answer: False

Step-by-step explanation:

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400 + 8 = 408

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2 years ago

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2 years ago

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Answer:

The answer would be C

Step-by-step explanation:

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2 years ago

A right triangle has one side that measures 4 in. The angle opposite that side measures 80o.

finlep [7]

Answer:

sin angle = opp/ hyp

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hyp = 4 in/ sin 80o

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2 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7B27x%5E%7B3%7Dy%5E%7B6%7D%20%20%7D" id="TexFormula1" title="\sqrt[6]{27x^{3}y^

bekas [8.4K]

Answer:

$\large\boxed{\sqrt[6]{27x^3y^6}=y\sqrt{3x}}$

Step-by-step explanation:

$\sqrt[6]{27x^3y^6}\qquad\text{use}\ \sqrt[n]{ab}=\sqrt[n]{a}\cdot\sqrt[n]{b}\\\\=\sqrt[6]{3^3}\cdot\sqrt[6]{x^3}\cdot\sqrt[6]{y^6}\qquad\text{use}\ \sqrt[n]{a^m}=a^\frac{m}{n}\\\\=3^\frac{3}{6}\cdot x^\frac{3}{6}\cdot y^\frac{6}{6}\qquad\text{simplify}\\\\=3^\frac{1}{2}\cdot x^\frac{1}{2}\cdot y^1\qquad\text{use}\ (ab)^n=a^n\cdot b^n\\\\=(3x)^\frac{1}{2}\cdot y\\\\=y\sqrt{3x}$

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2 years ago