The graph that would allow the comparison between the median number of teeth for mammals and reptiles easily is a Box Plot.
<h3>Median</h3>
The median of a set of data is the midpoint of values in a data set. It shows the value that divides the data set into two halves.
<h3>Box plot</h3>
- A box plot is a type of graph used in data analysis to visualize the distribution of numerical data and skewness by displaying the data quartiles and averages.
Box plots are also known as box and whisker plot.
- Box plots are used to compare visually differences among different samples or groups such medians, ranges, and outliers.
Therefore, the graph that would allow the comparison between the median number of teeth for mammals and reptiles easily is a Box Plot.
Learn more about Box plots and median at: brainly.com/question/16796572
If it is area your looking for.
Area = product of diagonal lengths divided by 2
Area = 12* 16 /2
=192/2 = 96.
IF it is the side length of the rhombus:
apply Pythagoras theorem since the diagonals always meet at 90°.
L =√(12² + 16²)
L= √400 = 20
Answer:
270cm^2
Step-by-step explanation:
The side length is irrelevant and does not matter.
The area of a triangle is found by multiplying the base by the height and then dividing that by two.
For this problem it would be...
30*18=540
540/2=270
So the area would be 270cm^2
The correct sequence of events in protein synthesis is transcription, then translation.
Answer:
0.095163
Step-by-step explanation:
given that a starter motor used in a space vehicle has a high rate of reliability and was reputed to start on any given occasion with probability .99999
Here we find that for any start, there are exactly two outcomes either success or failure.
Also each start is independent of the other since p = 0.99999 for succss is given constant.
Thus X no of successes is binomial with p = 0.99999 and n =10000
If Y is taken as failure then Y is binomial with p' = 0.00001 and n =10000
Required probability
= the probability of at least one failure in the next 10,000 starts
= 1-P(no failure in 10000 starts)
=