Let AB be the directed line segment beginning at point A(1,1) and ending at point B(15,-3). Find the point P on the line segment
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we know that
The sum of the internal angles in the triangle must be degrees
see the attached figure with letters to better understand the problem
Step
<u>Find the measure of the angle x</u>
In the triangle ABC
solve for x
therefore
<u>the answer Part a) is</u>
the measure of angle x is
Step
<u>Find the measure of the angle z</u>
we know that
--------> by supplementary angles
substitute the value of x
therefore
<u>the answer Part b) is</u>
the measure of angle z is
Step
<u>Find the measure of the angle y</u>
In the triangle ACD
solve for y
therefore
<u>the answer Part c) is</u>
the measure of angle y is
=[(sinx/cosx)/(1+1/cosx)] + [(1+1/cosx)/(sinx/cosx)]
=[(sinx/cosx)/(cosx+1/cosx)]+[(cosx+1/cosx)/(sinx/cosx)]
= [sinx/(cosx+1)] + [(cosx+1)/sinx]
= [sin^2x+(cosx+1)^2] / [sinx (cosx+1)]
= [2+2cosx] / [sinx(cosx+1)]
=[2(cosx+1)] / [sinx (cosx+1)]
= 2/sinx
= 2 cscx
(I think this will be helpful for you. if you can see the picture, it has more detail in it.)
=[(sinx/cosx)/(cosx+1/cosx)]+[(cosx+1/cosx)/(sinx/cosx)]
= [sinx/(cosx+1)] + [(cosx+1)/sinx]
= [sin^2x+(cosx+1)^2] / [sinx (cosx+1)]
= [2+2cosx] / [sinx(cosx+1)]
=[2(cosx+1)] / [sinx (cosx+1)]
= 2/sinx
= 2 cscx
(I think this will be helpful for you. if you can see the picture, it has more detail in it.)