Let AB be the directed line segment beginning at point A(1,1) and ending at point B(15,-3). Find the point P on the line segment
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Answer:
y = 10/9x + 9
Step-by-step explanation:
To write the equation in its slope-intercept form, y = mx + b, we need to find the slope (m) of the line and its y-intercept (b).
Given the points (0, 9) and (9, 19), we can solve for the slope of the line using the following formula:
Let (x1, y1) = (0, 9)
and (x2, y2) = (9, 19)
Substitute these values on the formula:
Therefore, the slope (<em>m </em>) = 10/9.
Next, the <u>y-intercept</u> is the point on the graph where it crosses the y-axis, and has the coordinates, (0, <em>b </em>). It is also the value of the y when x = 0.
One of the given points is the y-intercept of the line, given by (0, 9). The y-coordinate, 9, is the value of b.
Therefore, the linear equation in slope-intercept form is: y = 10/9x + 9