What is the equation of a line that passes through (-6, 2) and has a slope of `-(1)/(2)` ?
1 answer:
Answer:
B. `y = - (x)/(2) -1`
Step-by-step explanation:
The slope of the line = ![\[\frac{-1}{2}\]](https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7B-1%7D%7B2%7D%5C%5D)
So the general format of the line equation will be ![\[y=\frac{-1}{2}x + c\]](https://tex.z-dn.net/?f=%5C%5By%3D%5Cfrac%7B-1%7D%7B2%7Dx%20%2B%20c%5C%5D)
Also given that the line passes through the point (-6,2).
Substituting the values in the equation of the line,
![\[2=\frac{-1}{2}*(-6) + c\]](https://tex.z-dn.net/?f=%5C%5B2%3D%5Cfrac%7B-1%7D%7B2%7D%2A%28-6%29%20%2B%20c%5C%5D)
![\[=> 2=3 + c\]](https://tex.z-dn.net/?f=%5C%5B%3D%3E%202%3D3%20%2B%20c%5C%5D)
![\[=> c = -1\]](https://tex.z-dn.net/?f=%5C%5B%3D%3E%20c%20%3D%20-1%5C%5D)
So the line equation is ![\[y=\frac{-1}{2}x -1\]](https://tex.z-dn.net/?f=%5C%5By%3D%5Cfrac%7B-1%7D%7B2%7Dx%20-1%5C%5D)
Among the given options, option B is the correct one.
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