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loris [4]
3 years ago
13

What is the equation of a line that passes through (-6, 2) and has a slope of `-(1)/(2)` ?

Mathematics
1 answer:
Blizzard [7]3 years ago
5 0

Answer:

B.   `y = - (x)/(2) -1`

Step-by-step explanation:

The slope of the line = \[\frac{-1}{2}\]

So the general format of the line equation will be \[y=\frac{-1}{2}x + c\]

Also given that the line passes through the point (-6,2).

Substituting the values in the equation of the line,

\[2=\frac{-1}{2}*(-6) + c\]

\[=> 2=3 + c\]

\[=> c = -1\]

So the line equation is \[y=\frac{-1}{2}x -1\]

Among the given options, option B is the correct one.

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Jk is perpendicular to xy at its midpoint m. choose the answer that includes the correct responses.
Soloha48 [4]

Answer:

D

Step-by-step explanation:

JK intercept line XY at the midpoint. This means that these points are all equidistant from the midpoint. Due to this, J and K are both an equal distance from M. So is X and Y.

3 0
3 years ago
Find the prime factorization of 60, and then write in Standard Form, Expanded Form, and Exponential Form.
Katyanochek1 [597]
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6 0
3 years ago
You invested ​$26,000 in two accounts paying 2% and 3% annual​ interest, respectively. If the total interest earned for the year
mihalych1998 [28]

Answer:

You invested $22,000 in two accounts paying 3% and 5% annual interest, respectively. If the total interest earned for the year was $980, how much was invested at each rate?

Step-by-step explanation:

let x=amt invested at 3% rate of interest.

22000-x=amt invested at 5% rate of interest.  

.03x+.05(22000-x)=980

.03x+1100-.05x=980

.02x=120

x=6000

22000-x=16000

amt invested at 3% rate of interest=$6,000

amt invested at 5% rate of interest=$16,000

<h2><em><u>Hope iit help you mark as Brainlist</u></em></h2>
7 0
2 years ago
Find the area .............​
Natali5045456 [20]

Answer:

Area of the Trapezoid is=  13.5cm^2

Step-by-step explanation:

The given figure is in the shape of a trapezoid:

Area of a trapezoid= (1/2)*(Sum of parallel opposite sides)* (Distance between the parallel sides)

The parallel sides are: 6 cm and 3 cm

Distance between parallel sides= 3 cm

Area:

                    =\frac{1}{2} *(6+3)*3\\\\=\frac{1}{2}*9*3\\\\=\frac{27}{2} \\\\=13.5 cm^2

Area of the Trapezoid is=  13.5cm^2

5 0
3 years ago
Please help‍♂️ I forgot
vladimir2022 [97]
12 because the 23 3/8 is rounded down and the 11 2/9 is rounded down as well
3 0
3 years ago
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