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loris [4]
3 years ago
13

What is the equation of a line that passes through (-6, 2) and has a slope of `-(1)/(2)` ?

Mathematics
1 answer:
Blizzard [7]3 years ago
5 0

Answer:

B.   `y = - (x)/(2) -1`

Step-by-step explanation:

The slope of the line = \[\frac{-1}{2}\]

So the general format of the line equation will be \[y=\frac{-1}{2}x + c\]

Also given that the line passes through the point (-6,2).

Substituting the values in the equation of the line,

\[2=\frac{-1}{2}*(-6) + c\]

\[=> 2=3 + c\]

\[=> c = -1\]

So the line equation is \[y=\frac{-1}{2}x -1\]

Among the given options, option B is the correct one.

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Read 2 more answers
T is the midpoint of KL. K has coordinates (2,−6), and T has coordinates (−4,2). Identify the coordinates of L.
kotykmax [81]

Answer:

L = (-10,10)

Step-by-step explanation:

Given

K = (2,-6)

T = (-4,2)

Required

Determine the coordinates of L

Since T is the midpoint of K and L, we make use of:

T_x = \frac{K_x + L_x}{2}

and

T_y = \frac{K_y + L_y}{2}

Solving for L_x

T_x = \frac{K_x + L_x}{2}

-4 = \frac{2 + L_x}{2}

Multiply through by 2

-8 = 2 + L_x

L_x = -8 - 2

L_x = -10

Solving for L_y

T_y = \frac{K_y + L_y}{2}

2 = \frac{-6+L_y}{2}

Multiply through by 2

4 = -6 + L_y

L_y = 4 + 6

L_y = 10

Hence: The coordinates of L is:

L = (-10,10)

6 0
3 years ago
The square root of 61 is in between 2 integers what are they
swat32
One way is to estimate
1^2=1
2^2=4
3^2=9
4^2=16
5^2=25
6^2=36
7^2=49
8^2=64
the number 61 is between 49 and 64 therefor the square root of 61is between the intigers 7 and 8 or -7 and -8
8 0
3 years ago
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