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3 years ago

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Si sen A = 7/25 donde "A" pertenece al segundo cuadrante y el cos B = -4/5 donde "B" pertenece al segundo cuadrante Calcular cos

ec(A).cos(B).tan(A).cot(B)

1 answer:

lesya [120]3 years ago

3 0

Not sure just need answers because I don’t no the answers

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I need help if you answer this I will give you 5 stars, a thank you and a brainiest

grigory [225]

Answer:

200 / (3.14*(28/12)) = 27.3

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

-2=-(n-8) what would be the answer

Alexeev081 [22]

Answer:

n=10

Step-by-step explanation:

-2=-n+8

-n=-10

n=10

3 0

3 years ago

The vector ~v represents the displacement vector from Portland, Oregon to Houston, Texas. The vector w~ represents the displacem

Art [367]

Answer:

a

the displacement of the plane is $- \= w$

b

The displacement of plane from Portland to Akron with layover at Houston is

$\= v + \= w$

c

the vector which defines this displacement is $\= v + \= w =- 2500 \ km$

Step-by-step explanation:

From the question we are the

The displacement from Portland, Oregon to Houston, Texas. is $\= v$

The displacement from Houston, Texas to Akron, Ohio. is $\= w$ a

a

The motion of the plane in question a is in the opposite direction to vector $\= w$

So the displacement of the plane is $- \= w$

b

The motion of Portland to Houston to Akron is in the direction of both vector $\= v$ and $\= w$ so

The displacement of plane from Portland to Akron with layover at Houston is

$d = \= v + \= w$

c

From the question we are told that the plane flies over Portland to get to Anchorage, Alaska which implies that it is moving in opposite direction to the vector $\= v$

Give that distance from Portland to Houston is $\= v = 3000 km$

and the distance from Portland to Anchorage is $\= w = - 5500$ km

Then the vector which defines this displacement is mathematically represented as

$\= v + \= w = 3000 -5500$

$\= v + \= w =- 2500 \ km$

4 0

3 years ago

8a^3 b^8+4ab^5-16ab^8= <br> need help plz! (factor completely)

lakkis [162]

We can factor out the 4 to get
4(2a^3b^8+ab-4ab^8)
we can also factor out the ab
4ab(2a^2b^7+1-4b^7)
that is factored completely

6 0

3 years ago

A box of Munchkins contains chocolate and glazed donut holes. If Jacob ate 2 chocolate

neonofarm [45]

Answer:

24 munchkins.

Step-by-step explanation:

Let C be the number of chocolate and D be number of glazed donut holes in the original box.

We are told if Jacob ate 2 chocolate munchkins, then 1/11 of the remaining Munchkins would be chocolate. We can represent this information as:

$C-2=\frac{1}{11}*(C+D-2)...(1)$

We are also told if he instead added 4 glazed Munchkins to the original box, 1/7 of the Munchkins would be chocolate. We can represent this information as:

$C=\frac{1}{7}*(C+D+4)...(2)$

Upon substituting C's value from equation (2) in equation (1) we will get,

$\frac{1}{7}*(C+D+4)-2=\frac{1}{11}*(C+D-2)$

Let us have a common denominator on right side of equation.

$\frac{1}{7}*(C+D+4)-\frac{7*2}{7}=\frac{1}{11}*(C+D-2)$

$\frac{C+D+4-14}{7}=\frac{1}{11}*(C+D-2)$

Multiplying both sides of our equation by 7, we will get,

$7*\frac{C+D-10}{7}=7*\frac{1}{11}*(C+D-2)$

$C+D-10=\frac{7}{11}*(C+D-2)$

Multiplying both sides of our equation by 11, we will get,

$11*(C+D-10)=11*\frac{7}{11}*(C+D-2)$

$11*(C+D-10)=7*(C+D-2)$

$11C+11D-110=7C+7D-14$

$11C-7C+11D-7D=-14+110$

$4C+4D=96$

$4(C+D)=96$

$(C+D)=\frac{96}{4}$

$(C+D)=24$

Therefore, the total number of Munchkins in original box is 24.

3 0

3 years ago