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2 years ago

10

here will be 57 guests and he wants to make sure everyone gets a slice of cake. He wants to pay as little as possible for the ca

kes and for them to be the same size.

1 answer:

kicyunya [14]2 years ago

3 0

So what would the question be

You might be interested in

I WILL GIVE BRAINLIEST The area of the surface of the trampoline (square) is equal to twice its perimeter. Find the dimensions.

Brums [2.3K]

Given that the area is equal to twice the perimeter and the dimensions are:
length=4x ft, width=(x+6) ft
the perimeter will be:
P=2(L+W)
P=2(4x+(x+6))
P=2(4x+x+6)
P=2(5x+6)
P=(10x+12)

Area of the rectangle is:
A=4x(x+6)
A=4x²+24x
but:
2P=A
thus
2(10x+12)=4x²+24x
20x+24=4x²+24x
thus
4x²+4x-24=0
x²+x-6=0
x²-2x+3x-6=0
x(x-2)+3(x-2)=0
(x-2)(x+3)=0
thus the answer is:
x=-3 or x=2
thus
length=4x=4*2=8 ft
width=(x+6)=(2+6)=8 ft

4 0

3 years ago

Given the following formula, solve for I.<br> P =<br> 2(1 + b)

patriot [66]

Answer: $l=\dfrac{P}{2}-b$

<u>Step-by-step explanation:</u>

P = 2(l + b)

Divide both sides by 2:

$\dfrac{P}{2}=l+b$

Subtract b from both sides:

$\dfrac{P}{2}-b=l$

<em>Note: You can also multiply b by </em> $\frac{2}{2}$ <em> if you want the left side to be one fraction.</em>

$\dfrac{P}{2}-\bigg(\dfrac{2}{2}\bigg)b=l\\\\\\\dfrac{P-2b}{2}=l$

6 0

2 years ago

What are zero functions ?

puteri [66]

Answer:

A zero function is a function that is almost everywhere zero.

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Which relation IS a function? A.{(3, -2), (5, 1), (1, -1), (4, 4), (5, 4)} B.{(2, 3), (2, 2), (3, 4), (4, 3), (5, 0)} C.{(1, 5),

DIA [1.3K]

Answer:

Step-by-step explanation:

the answer is D because in D none of the x's repeat

4 0

2 years ago

Suppose that we have a right triangle $ABC$ with the right angle at $B$ such that $AC = \sqrt{61}$ and $AB = 5.$ A circle is dra

MaRussiya [10]

Answer:

CP = 6

Step-by-step explanation:

The length of segment BC is given by the Pythagorean theorem:

AC² = AB² +BC²

(√61)² = 5² + BC² . . . . . fill in the given numbers

61 -25 = BC² = 36 . . . . .subtract 25

BC = 6 . . . . . . . . . . . . . . take the square root

Since the center of the circle is on AB and is tangent to BC, it must pass through point B. That is, segment BC of length 6 is one of the tangent lines from point C. The other one, to point P, must be the same length, so ...

CP = 6

4 0

3 years ago