Ac=4 bx=y+4 doesn't make sense. Perhaps you meant <span>Ac-4bx=y+4. If this is not correct, ensure that you have copied down the original problem correctly.
</span>To solve Ac-4bx=y+4 for y, subtract 4 from both sides of this equation. You'll get:
Ac-4bx-4 = y+4 - 4, or y = ac-4bx - 4.
Answer:
The vertex is (3,4)
Step-by-step explanation:
f (x) = x^2 - 6 x + 13
Completing the square
-6/2 = -3 and squaring it = 9
= x^2 -6x +9 +4
= ( x-3) ^2 +4
The equation is now in vertex form
a( x-h) ^2 +k
where the vertex is ( h,k)
The vertex is (3,4)
