Question

Can anyone help me solve this

Answer 1

The diameter of the circle can be found by using the distance formula with the two points given...

d^2=(4--10)^2+(6--2)^2

d^2=14^2+8^2

d^2=260

d=√260

d=2√65

Since the radius is just half of the diameter, r= √65

The center of the circle will just be the midpoint (the average of the coordinates of the two endpoints) of the two points given so:

c=(-10+4)/2, (-2+6)/2

c=(-3,2)

The standard form of the circle is:

(x-h)^2+(y-k)^2=r^2, where (h,k) is the center of the circle so we can say:

(x+3)^2+(y-2)^2=65