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slava [35]
3 years ago
6

Find the exact value of tan(sin^-1((-12/13))

Mathematics
1 answer:
lidiya [134]3 years ago
8 0

Answer:

<em>2.399</em>

Step-by-step explanation:

Given the trigonometry expression:

tan(sin^-1((-12/13))

We are to find the exact value

tan(sin^-1((-12/13)) = tan(sin^-1((-0.9231))

tan(sin^-1((-12/13)) = tan(-67.38)

Also note that tan(-theta) = -tan theta

tan(-theta) = -tan67.38

tan(-67.38) = -2.399

<em>The exact value is 2.399</em>

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o-na [289]

Answer:

The volume of the cone is increasing at a rate of 1926 cubic inches per second.

Step-by-step explanation:

Volume of a right circular cone:

The volume of a right circular cone, with radius r and height h, is given by the following formula:

V = \frac{1}{3} \pi r^2h

Implicit derivation:

To solve this question, we have to apply implicit derivation, derivating the variables V, r and h with regard to t. So

\frac{dV}{dt} = \frac{1}{3}\left(2rh\frac{dr}{dt} + r^2\frac{dh}{dt}\right)

Radius is 107 in. and the height is 151 in.

This means that r = 107, h = 151

The radius of a right circular cone is increasing at a rate of 1.1 in/s while its height is decreasing at a rate of 2.6 in/s.

This means that \frac{dr}{dt} = 1.1, \frac{dh}{dt} = -2.6

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This is \frac{dV}{dt}. So

\frac{dV}{dt} = \frac{1}{3}\left(2rh\frac{dr}{dt} + r^2\frac{dh}{dt}\right)

\frac{dV}{dt} = \frac{1}{3}(2(107)(151)(1.1) + (107)^2(-2.6))

\frac{dV}{dt} = \frac{2(107)(151)(1.1) - (107)^2(2.6)}{3}

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The volume of the cone is increasing at a rate of 1926 cubic inches per second.

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e.g. if 2019 had $1 net worth and 2020 had $2 net worth, since 2>1 it would be |2-1| = 1. If 2019 had $2 net worth and 2020 had $1 net worth, since 1<2 there would be a - |2-1| = -1 net change.

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the gravitational attraction between two masses varies inversely as the square of the distance between them. if the attraction f
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Answer:

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Step-by-step explanation:

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