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Y_Kistochka [10]
3 years ago
7

Missy uses 1 hexagonal, 2 rectangular, and 5 triangular pieces of fabric to make 1 bug design for a quilt. If she uses 80 pieces

in all to make bug designs, how many of each shape does she use? Enter the correct answer.
Mathematics
1 answer:
katrin [286]3 years ago
5 0

Answer:

10 Hexagonal pieces, 20 Rectangular pieces and 50 Triangular pieces.

Step-by-step explanation:

First let's check how many pieces Missy uses to make one bug design:

1 hexagonal + 2 rectangular + 5 triangular = 8 total pieces.

Is the uses 80 pieces in total, she made a total of 80/8 = 10 bug designs

So now we can calculate how many pieces of each shape she uses just multiplying the amount of bug designs (10) by the number of pieces of each shape:

Hexagonal pieces: 1 * 10 = 10 pieces

Rectangular pieces: 2 * 10 = 20 pieces

Triangular pieces: 5 * 10 = 50 pieces

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What is the prime factorization 10,000 using exponent's?
Ymorist [56]

Answer: 10 to the 3rd power

Step-by-step explanation: 10 times 10 times 10 equals 10,000

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3 years ago
OAA', OBB', and OCC' are straight lines. Triangle ABC is mapped onto Triangle A'B'C' by an enlargement with center O. What is th
bazaltina [42]

Answer:

(D) 2

Step-by-step explanation:

The scale factor of the enlargement of ΔABC to ΔA'B'C' is given by the ratio of the length of the corresponding sides of ΔA'B'C' and ΔABC

Therefore, we have;

The \ scale \ factor = \dfrac{Length \ of \overline  {B'C'}}{Length \ of \overline {BC}} =  \dfrac{Length \ of \overline  {A'C'}}{Length \ of \overline {AC}} =  \dfrac{Length \ of \overline  {A'B'}}{Length \ of \overline {AB}}

\dfrac{Length \ of \overline  {B'C'}}{Length \ of \overline {BC}} =  \dfrac{2 \ units}{1 \ unit} = 2

\dfrac{Length \ of \overline  {A'C'}}{Length \ of \overline {AC}} =  \dfrac{4 \ units}{2 \ units} = 2

\dfrac{Length \ of \overline  {A'B'}}{Length \ of \overline {AB}} =  \dfrac{2 \cdot \sqrt{5}  \ units}{\sqrt{5}  \ units} = 2

Therefore, the scale factor = 2

6 0
3 years ago
A 64-foot tall monument casts a shadow 16 feet long. If Kyle is stsnding nearby and is 6'3 tall, find the length of his shadow.​
Helen [10]

Answer: Length of his shadow is 18 feet.

Step-by-step explanation:

Since we have given that

Length of tall monument = 64 foot

Length of shadow = 16 feet

Length of pole where Kyle is standing = 6 feet 3 inch = 72 inches

So, we need to find the length of its shadow.

So, according to question, we get that

\dfrac{64\times 12}{16\times 12}=\dfrac{72}{x}\\\\4=\dfrac{72}{x}\\\\4x=72\\\\x=\dfrac{72}{4}\\\\x=18\ feet

Hence, length of his shadow is 18 feet.

3 0
3 years ago
6th grade math help me please ! :))
Stells [14]

Answer:

1,825 days

Step-by-step explanation:

730 / 2 = 365 (one year, or the number of days a single revolution around the sun takes)

Now just multiply by 5

[365 · 5 = 1,825], thus 1,825 days are the duration of 5 revolutions.

The problem could also be initially expressed as:

x = (720/2) · (5) with x representing the missing value

6 0
3 years ago
There are 16 pieces of fruit in a basket, including 2 nectarines. What is the probability that a randomly selected piece of frui
aleksklad [387]

Answer:

The probability is 1/8

Step-by-step explanation:

We have 2 nectarines in a total of 16 pieces of fruit in a basket, so the probability of random selected piece of fruit being a nectarine is the number of nectarines over the total number of pieces of fruit:

Probability = Number of nectarines / Total pieces = 2 / 16

To find the fraction in the simplest form, we divide the numerator and denominator by 2:

Probability = (2/2) / (16/2) = 1/8

3 0
3 years ago
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