So here is how we are going to prove that (2(tan x - cot x) / (tan^2 x - cot^2 x} = sin (2x). Follow it step by step: LS = 2(tanx−cotx) ------------------ tan^2−cot^2x = 2(tanx−cotx) ---------------------- (tanx−cotx)(tanx+cotx) = 2 ------------------- (tanx+cotx) = 2 ----------------- Sin2x+cos2x ---------------- sinxcosx = 2 ------------- 1 ------------ sinxcosx = 2sinxcosx = sin2x I hope that is the answer that you are looking for. Let me know if you need more help next time. Thanks for posting your question here in brainly!