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2 years ago

Will mark brainliest for having the steps. prove tan(2x) = tan(x+x)

2 answers:

5 0

Answer:

tan(2x)=tan(x+x)

tan(x+x)

tan(x)+tan(x)/1-tan(x)tan(x)

2tan(x)/1-tan(x)^2

tan(2x)

tan(2x)=tan(x+x) is True.

jonny [76]2 years ago

4 0

So here is how we are going to prove that (2(tan x - cot x) / (tan^2 x - cot^2 x} = sin (2x). Follow it step by step:
LS = 2(tanx−cotx)
------------------
tan^2−cot^2x
= 2(tanx−cotx)
----------------------
(tanx−cotx)(tanx+cotx)
= 2
-------------------
(tanx+cotx)
= 2
-----------------
Sin2x+cos2x
---------------- sinxcosx
= 2
-------------
1
------------
sinxcosx
= 2sinxcosx
= sin2x
I hope that is the answer that you are looking for. Let me know if you need more help next time. Thanks for posting your question here in brainly!

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A percent is a fraction whose denominator is 100.

Softa [21]

That is partially a true statement. The percent is the numerator of the fraction who's denominator is 100.

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3 years ago

In a circle, a 90° sector has area 16π ft2. What is the radius of the circle?

Veronika [31]

Sector area = 0.5 * r^2 * angle (in radians)

so:

16 pi = 0.5 * r^2 * (90*pi/180)

r^2 = 16 pi /(0.25 pi) = 64

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therefore it would be d

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2 years ago

HeLp mE fast! 5 Stars and Thanks!

Mice21 [21]

Answer:

6 3/16

Step-by-step explanation:

4 9/16=73/16

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8 0

3 years ago

Read 2 more answers

Convert 1 cal/(m^2 * sec * °C) into BTU/(ft^2 * hr * °F)

Crazy boy [7]

Answer:

$1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

Step-by-step explanation:

To find : Convert $1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}$ into $\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

Solution :

We convert units one by one,

$1\text{ m}^2=10.7639\text{ ft}^2$

$1\text{ sec}=\frac{1}{3600}\text{ hour}$

$1\text{ cal}=0.003968\text{ BTU}$

Converting temperature unit,

$^\circ C\times \frac{9}{5}+32=^\circ F$

$1^\circ C\times \frac{9}{5}+32=33.8^\circ F$

So, $1^\circ C=33.8^\circ F$

Substitute all the values in the unit conversion,

$1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=\frac{0.003968}{10.7639\times \frac{1}{3600}\times 33.8}\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

$1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=\frac{0.003968}{0.101061}\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

$1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

Therefore, The conversion of unit is $1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

3 0

3 years ago

Theoretical probability is the probability that an event occurs when all of the outcomes of the experiment are equally likely.

MA_775_DIABLO [31]

1. The probability that we select a red marble is 1/3.

We found this out by taking the amount of red marbles there are and the total amount of marbles. The total amount of marbles is 18 and there are red marbles. So, it would become 6 out of 18 or 6/18. Then, we simplify 6/18 to the simplest form. The greatest common factor of both of those numbers is 6. Lastly, we divide each of them by 6 to get the simplest form.

6/18 = (6/6)/(18/6)

(6/6)/(18/6) = 1/3

So, therefore, the theoretical probability of picking a red marble is 1/3.

2. The probability that we select a blue marble is 2/3.

We can find this out by taking the amount of blue marbles there are and the total amount of marbles. We know that the total amount of marble is 18 and there are 12 blue marbles. So, we simply get the GCF (greatest common factor) and divide them by it.

Greatest Common Factor of 12 and 18 = 6

12/18 = (12/6)/(18/6)

(12/6)/(18/6) = 2/3

Thus, the theoretical probability of picking a blue marble is 2/3.

4 0

3 years ago