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iren2701 [21]
3 years ago
11

What is the difference in solving functions when giving the following information: f(x)=2 and f(2)

Mathematics
1 answer:
vfiekz [6]3 years ago
6 0

<em>*Remember that y and f(x) are the same.</em>

With f(2), you are solving for the output (y), given that the input (x) is equal to 2.

With f(x) = 2, you are solving for the input (x), given that the output (y) is equal to 2.

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P(x)=2x^3-11x^2+ax-40 if x+4 is a factor of this polynomial what is the value of a
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Answer:

a = -86.

Step-by-step explanation:

By the Factor Theorem, if x + 4 is a factor then P(-4) = 0, so:

P(-4) = 2(-4)^3 - 11(-4)^2 + a(-4)- 40 = 0

-128 - 176 - 4a - 40 = 0

-4a = 128 +176 + 40

-4a = 344

a = -86.

3 0
3 years ago
Edge: Which equation has a focus at (–6, 12) and directrix of x = –12?
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Answer:

C) (y - 12)^2 = 12(x+9)

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Please help!!! i cant figure it out
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Step-by-step explanation:

Hi there!

Given;

f(x) = 17x + 9

h(x) = 4x

To find: f(x)-h(x)

f(x)-h(x)= 17x + 9 - 4x

= 13x + 9

Therefore, f(x)-h(x) = 13x + 9.

<u>Hope it helps!</u>

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2 years ago
An asteroid is 10^15 miles away from earth, and it is traveling at a speed of 10^5 miles a day.
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Triangle abc is such that ab=4 and ac=8 if m is the midpoint of bc and am=3, what is the length of bc?
zavuch27 [327]
This is an interesting question. I chose to tackle it using the Law of Cosines.
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  AM² = AB² + MB² - 2·AB·MB·cos(B)
Subtracting twice the second equation from the first, we have
  AC² - 2·AM² = -AB² + BC² - 2·MB²

We know that MB = BC/2. When we substitute the given information, we have
  8² - 2·3² = -4² + BC² - BC²/2
  124 = BC² . . . . . . . . . . . . . . . . . . add 16, multiply by 2
  2√31 = BC ≈ 11.1355

4 0
3 years ago
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