Answer:
The answer to the question is
It take for the golf ball hit on Mars to reach the ground 8.284 s longer.
Step-by-step explanation:
To Solve the question, we note that the equation of motion is given to us as
h = -1.9·t² + 26·t
Therefore the height
We compare the above equation with the equation of of motion
S = ut - 0.5×g×t² where u = initial velocity = 26 m/s and - 0.5×g = -1.9
Therefore the acceleration due to gravity om mars = -1.9/-0.5 = 3.8 m/s²
We now have the time taken to maximum height given by
v = u - g·t where v = 0 at maximum height
We therefore have u = g·t → 26 = 3.8×t or t = 26/3.8 = 6.84 seconds
The time taken for ball to hit the ground is 2 × the time to reach maximum height = 2 × 6.84 = 13.684 s
The time longer it takes for the ball on Mars to complete the path up to maximum height and down again is 13.684 s - 5.4 s = 8.284 s.
The answer is:
7 miles
5+2=7
50 pairs of whole numbers
Answer:
Step-by-step explanation:
4a² b³ * (9a⁴b² - 4a² + 3) = 4a²b³ * 9a⁴b² - 4a²b³*4a² + 4a²b³*3
= 36a²⁺⁴ b³⁺² -16a²⁺²b³ + 12a²b³
= 36a⁶b⁵ - 16a⁴b³ + 12a²b³
