There is no question so currently, I am unable to help you.
Answer:
x=13 /6
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
We are given that the position of a particle is modeled by the function:
And we want to find the times for which the <em>speed</em> of our particle is <em>increasing. </em>
In other words, we want to find the times for which our <em>acceleration</em> is positive (a(t)>0).
So first, we will find our acceleration function. We can differentiate twice.
By taking the derivative of both sides with respect to <em>t</em>, we acquire:
Differentiate:
This is our velocity function. We can differentiate once more to acquire the acceleration function. Therefore:
Differentiate:
If our speed is increasing, our acceleration must be positive. So:
By substitution:
Now, we can solve for <em>t:</em>
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Therefore, the only interval for which the speed of the particle is increasing (i.e. the acceleration is positive) is for all times t>4.
So, our answer is B.
-8 and 7.
Use the quadratic formula or factor and set equal to 0.
Answer:
Step-by-step explanation:
- −2x + 5(x − 2) > 7x − 6
- -2x + 5x - 10 > 7x - 6
- 3x - 7x > - 6 + 10
- -4x > 4
- x < - 1
- x = (-∞, -1)
The graph is all points to the left from -1, where -1 is not included