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koban [17]
4 years ago
9

Solve for b by elimination 2a+3b=12 5a-b=13

Mathematics
1 answer:
Dima020 [189]4 years ago
6 0

Answer: 2a+3b=12

               b=(12-2a)/3

5a-b=13

b= -13+5a

Step-by-step explanation:

1) 2a+3b=12

-2a        -2a

3b=12-2a

/3         /3

b= (12-2a)/3

2) 5a-b=13

   -5a     -5a

-b=13-5a    

*-1   *-1   -b= 13(-1)-5a(-1) *you'd multiply by -1 to cancel out the negative on b*

b= -13+5a

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Answer:

Equation of a line that passes through the point ( 6,-3 ) and is parallel to the graph of y = 3x + 1 is \mathbf{y=3x-21}

Step-by-step explanation:

We need to write equation of a line that passes through the point ( 6,-3 ) and is parallel to the graph of y = 3x + 1

The equation will be in slope-intercept form i.e y=mx+b where m is slope and b is y-intercept.

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Since the lines are parallel to each other, their slopes will be equal.

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Equation of required line

The equation of required line having slope m=3 and y-intercept b = -21 is:y=mx+b\\y=3x-21

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