Answer:
70°
Step-by-step explanation:
Connect the center of the circle with endpoints of the chord. Let the center of the circle be point O and endpoints of the chord be points A (let point A lie on the tangent line too)and B.
From the figure, central angle AOB has the measure of 220°.
Consider triangle AOB. This triangle is isosceles triangle because OA and OB are both radii. In this triangle the measure of angle AOB is 360° - 220° = 140°.
Angles OAB and OBA are angles adjacent to the base AB, so they are congruent. The sum of the measures of all interior angles in triangle is always 180°, so
m∠OAB + m∠OBA + m∠AOB = 180°
m∠OAB = m∠OBA = 1/2 (180° - 140°)
m∠OAB = 20°
Since drawn line is tangent line, then OA is perpendicular to this tangent line and
x° = 90° - 20°
x° = 70°
Answer:
5/6
Step-by-step explanation:
2 1/2 -> 5/2
5/2 divided by 3, which is 0.83333333333
0.83333333333 as a simplied fraction is 5/6
Point slope form says the line through (a,b) with slope m is
y - b = m(x - a)
Here that's
y - 32 = -6(x - -6)
y -32 = -6(x + 6) = -6x - 36
y = -6x - 4
Check:
-6(-6) - 4 = 36 - 4 = 32, good
Answer: y = -6x - 4
Answer:
B)
x units
Step-by-step explanation:
Let quadrilateral KMPT be a rectangle with dimensions 12 units by 8 units. Then its perimeter would be equal to:
Perimeter of a rectangle = 2 (l + b)
where: l is the length = 12 units and b is the breadth = 8 units. So that:
Perimeter of KMPT = 2 (12 + 8)
= 40 units
Dilating KMPT by a scale factor of
would create K'M'P'T' of dimensions;
× 12 units by
× 8 units. Thus, the dimensions of K'M'P'T' would be 9 units by 6 units.
Perimeter of K'M'P'T' = 2 (l + b)
= 2(9 + 6)
= 30 units
Comparing the perimeters of KMPT and K'M'P'T', the perimeter of K'M'P'T' would be
× perimeter of KMPT.
Therefore, if the perimeter of KMPT is x units, then;
perimeter of K'M'P'T' =
* x units
=
x units