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3 years ago

How do you solve the linear equation using multiplication with the elimination method?

1 answer:

4 0

3x+2y=11--------x1
7x-y=3------------x2

3x+2y=11---equ 1
14x-2y=6---equ 2

equ 1+ equ 2 will eliminate y
17x=17
x=1
then put x=1 in equ 1
3(1)+2y=11
2y=11-3
2y=8
y=8/2
y=4

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P and q are prime numbers <br> P³×q=56<br> Find p and q

aksik [14]

Answer:

Step-by-step explanation:

p has to be pretty small because it is cubed. 3 doesn't work because 3 cubed = 27 which does not divide into 56.

So we should try p = 2

2^3 = 8

56 / 8 = 7

2 is prime

7 is prime

p = 2

q = 7

5 0

3 years ago

Read 2 more answers

X is less than or equal to 1

levacccp [35]

Answer:

X is equal to 1, because for any other number x, 1*x = x. So, the reason that any number to the zero power is one is because any number to the zero power is just the product of no numbers at all.

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4 years ago

Her gross pay at the end of 7 work day is 35h + 56 dollars. What expression represents her gross pay each day

Vladimir [108]

(35h + 56) / 7 or 5h + 8

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3 years ago

Rework problem 15 in section 2 of Chapter 5 of your textbook about the growing suburb and the declining city using the following

bazaltina [42]

Answer:

16 years.

Step-by-step explanation:

Please consider the complete question.

Assume that the suburb has a population of 686,000 and is growing at a rate of 4000 per year. Assume that the city has a population of 942,000 and is declining at a rate of 12000 per year. In how many years will the populations of the suburb and the city be equal?

Let x represent number of years.

Growth function would be $G(x)=4000x+686,000$ and decline function would be $D(x)=942,000-12,000x$ .

To find the time when both populations will be equal, we will equate both functions as:

$4000x+686,000=942,000-12,000x$

$4000x+12,000x+686,000=942,000$

$16,000x+686,000=942,000$

$16,000x=942,000-686,000$

$16,000x=256,000$

$\frac{16,000x}{16,000}=\frac{256,000}{16,000}$

$x=16$

Therefore, in 16 years the populations of the suburb and the city will be equal.

6 0

3 years ago

Needed help with this question!

In-s [12.5K]

A) is 2x
b) is $x^{3}$
c) is -2x

I think these are correct.
$log_{10}1000^{x] = log_{10}10^{2x}=2x$
I did similar things to get other answers
$1000^{log_{10}x} = 10^{3log_{10}x}=10^{log_{10}x^{3}}=x^{3}$

5 0

3 years ago