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andrezito [222]
3 years ago
13

Rework problem 15 in section 2 of Chapter 5 of your textbook about the growing suburb and the declining city using the following

data: Assume that the suburb has a population of 686000 and is growing at a rate of 4000 per year. Assume that the city has a population of 942000 and is declining at a rate of 12000 per year.
Mathematics
1 answer:
bazaltina [42]3 years ago
6 0

Answer:

16 years.

Step-by-step explanation:

Please consider the complete question.

Assume that the suburb has a population of 686,000 and is growing at a rate of 4000 per year. Assume that the city has a population of 942,000 and is declining at a rate of 12000 per year. In how many years will the populations of the suburb and the city be equal?

Let x represent number of years.  

Growth function would be G(x)=4000x+686,000 and decline function would be D(x)=942,000-12,000x.

To find the time when both populations will be equal, we will equate both functions as:

4000x+686,000=942,000-12,000x

4000x+12,000x+686,000=942,000

16,000x+686,000=942,000

16,000x=942,000-686,000

16,000x=256,000

\frac{16,000x}{16,000}=\frac{256,000}{16,000}

x=16

Therefore, in 16 years the populations of the suburb and the city will be equal.

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Answer:

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If we compare the p value and a significance level for example \alpha=0.1 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean it's not significantly less than 20 min.

Step-by-step explanation:

Data given and notation    

\bar X=18.81 represent the average lateral recumbency for the sample    

s=8.4 represent the sample standard deviation    

n=75 sample size    

\mu_o =20 represent the value that we want to test    

\alpha represent the significance level for the hypothesis test.    

t would represent the statistic (variable of interest)    

p_v represent the p value for the test (variable of interest)    

State the null and alternative hypotheses.    

We need to apply a left tailed  test.  

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Alternative hypothesis :\mu < 20  

Compute the test statistic  

The statistic for this case is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)    

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

Calculate the statistic    

We can replace in formula (1) the info given like this:    

t=\frac{18.81-20}{\frac{8.4}{\sqrt{75}}}=-1.227

The degrees of freedom are given by:

df=n-1=75-1=74    

Give the appropriate conclusion for the test  

Since is a one side left tailed test the p value would be:    

p_v =P(t_{74}    

Conclusion    

If we compare the p value and a significance level for example \alpha=0.1 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean it's not significantly less than 20 min.

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