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Anton [14]
3 years ago
5

Prove the identity (sina-cosatanb)/(cosa+sinatanb) = tan (a+b)

Mathematics
1 answer:
OLga [1]3 years ago
7 0
Sina - (cosa)(tanb)/cosa + (sina)(tanb)
sina ≡ (tana)(cosa)

(tana)(cosa) - (cosa)(tanb)/cosa + (tana)(cosa)(tanb)
= cosa(tana - tanb)/cosa(1 + tanatanb)
(cosas cancel out)
= (tana - tanb)/(1 + tanatanb) ≡ tan(a-b)
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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