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2 years ago

Triangle with exactly 2 equal sides

Mathematics

2 answers:

oee [108]2 years ago

7 0

It’s an isosceles. Two sides are the same and the two angles are the same

r-ruslan [8.4K]2 years ago

4 0

Hey there!

ALL triangles has 3 sides. (Top and the two corners)

The only try that has the sides that are equal to each other is, the isosceles triangle ; the isosceles triangle is equal to 180°

Answer: ISOSCELES TRIANGLE ☑️

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)

Here’s an example SIDE A is EQUIVALENT (EQUAL) to SIDE B

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The sum of three numbers is 8. twice the smaller is 2 less than the largest, while the sum of the largest and smallest is 5. use

Lorico [155]

X + Y + Z = 8
2x = Z - 2
X + Z = 5
X = 1
1 + Y + Z = 8
Y + Z = 6
1 + Z = 5
Z = 4
1 + Y + 4 = 8
5 + Y = 8
Y = 3
The variables are 1, 3, 4.

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3 years ago

Consider the arithmetic sequence 13, 16, 19, 22, 25, ...<br> What is the 60th term in the sequence?

Pavel [41]

Answer:

180

Step-by-step explanation:

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3 years ago

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-10(n+30)=1/2(24-14n)

Pavel [41]

N = -104 is the correct answer

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2 years ago

Consider f and c below. f(x, y) = x2 i + y2 j c is the arc of the parabola y = 2x2 from (−1, 2) to (1, 2) (a) find a function f

Korvikt [17]

If there is some scalar function $f(x,y)$ such that

$\nabla f(x,y)=\mathbf f(x,y)=x^2\,\mathbf i+y^2\,\mathbf j$

then we want to find $f$ such that

$\dfrac{\partial f}{\partial x}=x^2\implies f(x,y)=\dfrac{x^3}3+g(y)$
$\dfrac{\partial f}{\partial y}=y^2=\dfrac{\mathrm dg}{\mathrm dy}\implies g(y)=\dfrac{y^3}3+C$
$\implies f(x,y)=\dfrac{x^3}3+\dfrac{y^3}3+C$

So the vector field $\mathbf f(x,y)$ is conservative, which means the fundamental theorem applies; the line integral of $\mathbf f$ along any path $\mathcal C$ parameterized by some vector-valued function $\mathbf r(t)$ over $a\le t\le b$ is given by

$\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=\int_{t=a}^{t=b}\mathbf f(\mathbf r(t))\cdot\dfrac{\mathrm d\mathbf r}{\mathrm dt}\,\mathrm dt=f(\mathbf r(b))-f(\mathbf r(a))$

In this case,

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2 years ago

how much antifreeze 25% antifreeze and 50% antifreeze should be combined to give 40 gallon of 30% antifreeze?

VARVARA [1.3K]

32 gallons of 25 % antifreeze should be combined with 8 gallons of 50 % antifreeze to get 40 gallon of 30% antifreeze

<h3><u>Solution:</u></h3>

From given,

Final mixture is 40 gallon

Let "x" be the gallon of 25 % antifreeze

Then, (40 - x) is the gallon of 50 % antifreeze

Therefore, according to question,

"x" gallons of 25 % antifreeze should be combined with (40 - x) gallons of 50 % antifreeze to get 40 gallon of 30% antifreeze

<h3><u>Therefore, we frame a equation as:</u></h3>

25 % of x + 50 % of (40 - x) = 30 % of 40

Solve for "x"

$\frac{25}{100} \times x + \frac{50}{100} \times (40-x) = \frac{30}{100} \times 40\\\\0.25x + 0.5(40-x) = 12\\\\0.25x + 20 - 0.5x = 12\\\\0.25x - 0.5x = 12 - 20\\\\-0.25x = -8\\\\0.25x = 8\\\\Divide\ both\ sides\ by\ 0.25\\\\x = 32$

Thus, 32 gallons of 25 % antifreeze is used

Then, (40 - x) = (40 - 32) = 8

Thus 8 gallons of 50 % antifreeze is used

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2 years ago