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vredina [299]
3 years ago
6

What is the slope of the line through (-1,2) and (-3,2)

Mathematics
1 answer:
Dafna1 [17]3 years ago
8 0

Answer:

0/-2; undefined

Step-by-step explanation:

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Root99 + root44<br> can someone help?
iogann1982 [59]

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here I worked it out on my calculator so it should be right

5 root 11

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I suck at math don't judge.. 9/8 divided by 3/6 =? i got an answer just don't know if i'm correct
olga nikolaevna [1]
Its 2.25 I believe ..............
4 0
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Simplify: (-20)4 ÷ (-20)1 <br> A.(-20)4<br> B. (-20)5<br> C. -201 <br> D.(-20)3
Bezzdna [24]
A. (-20)4
Hope this helped! With love, Eilyssa! :)
3 0
4 years ago
Read 2 more answers
What is the circumstance of 12cm ?
konstantin123 [22]

Answer:

37.68 cm

Step-by-step explanation:

The formula for circumference is C= 2* (3.14) r

First you can actually cut 12 by 1/2

12 * 1/2  is 6.  This works because 12 is an even number.

2 * 3.14 (6) gives you 37.68 cm.

So i believe the answer is 37.68 cm.

8 0
3 years ago
A N S W E R Q U I C K P L E A S E
chubhunter [2.5K]

Answer:

1. A

2. D

3. D

Step-by-step explanation:

The standard form of a parabola is

y=\frac{1}{4p}(x-h)^2+k            ..... (1)

Where, (h,k) is vertex, (h,k+p) is focus and y=k-p is directrix.

1. The directrix of a parabola is y=−8 . The focus of the parabola is (−2,−6) .

k-p=-8                   ...(a)

(h,k+p)=(-2,-6)

k+p=-6            .... (b)

h=-2

On solving (a) and (b),  we get k=-7 and p=1.

Put h=-2, k=-7 and p=1 in equation (1).

y=\frac{1}{4(1)}(x-(-2))^2+(-7)

y=\frac{1}{4}(x+2)^2-7

Therefore option A is correct.

2 The directrix of a parabola is the line y=5 . The focus of the parabola is (2,1) .

k-p=5                   ...(c)

(h,k+p)=(2,1)

k+p=1            .... (d)

h=2

On solving (c) and (d),  we get k=3 and p=-2.

Put h=2, k=3 and p=-2 in equation (1).

y=\frac{1}{4(-2)}(x-(2))^2+(3)

y=-\frac{1}{8}(x-2)^2+3

Therefore option D is correct.

3. The focus of a parabola is (0,−2) . The directrix of the parabola is the line y=−3 .

k-p=-3                   ...(e)

(h,k+p)=(0,-2)

k+p=-2            .... (f)

h=0

On solving (e) and (f),  we get k=-2.5 and p=0.5.

Put h=0, k=-2.5 and p=0.5 in equation (1).

y=\frac{1}{4(0.5)}(x-(0))^2+(-2.5)

y=\frac{1}{2}(x)^2-2.5

y=\frac{1}{2}(x)^2-\frac{5}{2}

Therefore option D is correct.

5 0
3 years ago
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