Answer:
256/3 = 85 1/3 square inches
Step-by-step explanation:
The dimensions of the first inscribed triangle are 1/2 those of the original, so its area is (1/2)² = 1/4 of the original. The area of the original is ...
A = (1/2)bh = (1/2)(16/√2)(16/√2) = 64 . . . . square inches
The sum of an infinite series with first term 64 and common ratio 1/4 is ...
S = a1/(1 -r) . . . . . . for first term a1 and common ratio r
= 64/(1 -1/4) = 64(4/3) = 256/3 . . . . square inches
The sum of the areas of the triangles is 256/3 = 85 1/3 square inches.
Answer:
A
Step-by-step explanation:
cause im smart
Alright, lets get started.
The answer Sandra got is correct that is zero but there are some mistakes she made while writing steps.
Incorrect step
Because as per even/odd identity,
Cot (-Θ) = - cot (Θ)
Hence
Now,
It could be written as
0
Hence the answer is 0. : Answer
Hope it will help :)
Answer:
a) 47
b) 3
c) 1
d) 2
e) 47
f) 3
Step-by-step explanation:
read the textbook
