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kirill [66]
3 years ago
14

18 POINTS HELLLPPPpppppppppp

Mathematics
1 answer:
anygoal [31]3 years ago
3 0
26 and 151? Because im confused to death srry if it doesnt help. I tryed.
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What does it mean to square a number? Provide an example to support your answer.
shutvik [7]

Answer:

When squaring a number it is essentially taking a number and multiplying it by itself. For example, 5^2 is 5×5 (=25).

5 0
2 years ago
A species of bacteria is 10 micrometers long. A virus is 10,000 times smaller than bacteria. a. Using the table above, find the
stich3 [128]

Answer:

10^{-4} times 10 micrometers (or 10^{-5}) is 10^{-9}

8 0
3 years ago
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Suppose twenty-two communities have an average of = 123.6 reported cases of larceny per year. assume that σ is known to be 36.8
Delvig [45]
We are given the following data:

Average = m = 123.6
Population standard deviation = σ= psd = 36.8
Sample Size = n = 22

We are to find the confidence intervals for 90%, 95% and 98% confidence level.

Since the population standard deviation is known, and sample size is not too small, we can use standard normal distribution to find the confidence intervals.

Part 1) 90% Confidence Interval
z value for 90% confidence interval = 1.645

Lower end of confidence interval = m-z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Lower end of confidence interval=123.6-1.645* \frac{36.8}{ \sqrt{22}}=110.69

Upper end of confidence interval = m+z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Upper end of confidence interval=123.6+1.645* \frac{36.8}{ \sqrt{22}}=136.51

Thus the 90% confidence interval will be (110.69, 136.51)

Part 2) 95% Confidence Interval
z value for 95% confidence interval = 1.96

Lower end of confidence interval = m-z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Lower end of confidence interval=123.6-1.96* \frac{36.8}{ \sqrt{22}}=108.22

Upper end of confidence interval = m+z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Upper end of confidence interval=123.6+1.96* \frac{36.8}{ \sqrt{22}}=138.98

Thus the 95% confidence interval will be (108.22, 138.98)

Part 3) 98% Confidence Interval
z value for 98% confidence interval = 2.327

Lower end of confidence interval = m-z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Lower end of confidence interval=123.6-2.327* \frac{36.8}{ \sqrt{22}}=105.34
Upper end of confidence interval = m+z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Upper end of confidence interval=123.6+2.327* \frac{36.8}{ \sqrt{22}}=141.86

Thus the 98% confidence interval will be (105.34, 141.86)


Part 4) Comparison of Confidence Intervals
The 90% confidence interval is: (110.69, 136.51)
The 95% confidence interval is: (108.22, 138.98)
The 98% confidence interval is: (105.34, 141.86)

As the level of confidence is increasing, the width of confidence interval is also increasing. So we can conclude that increasing the confidence level increases the width of confidence intervals.
3 0
3 years ago
What is the simplified form of the square root of 45?
Elodia [21]

Answer:

3sqrt(5)

Step-by-step explanation:

sqrt(45)

sqrt(9*5)

We know the sqrt(ab) = sqrt(a) sqrt(b)

sqrt(9) sqrt(5)

3sqrt(5)

6 0
2 years ago
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Solve the equation 15p2 + 7p − 4 = 0 by completing the square.
natulia [17]

Answer:

p=0 or p=-7/15

Step-by-step explanation:

15p2+7p=0

p(15p+7)=0

p=0 or 15p+7=0

4 0
1 year ago
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