It is c, 2 -4 no solution
Using the normal distribution, it is found that the correct option is:
- P(Y< 16) = 0.041. About 4.1% of all toco toucans weigh less than 16 ounces
In a normal distribution with mean and standard deviation , the z-score of a measure X is given by:

- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
In this problem:
- Mean of 20 ounces, hence
.
- Standard deviation of 2.3 ounces, hence

P(Y < 16) is the <u>p-value of Z when X = 16</u>, hence:



has a p-value of 0.041.
This is valid for the entire population, hence, the correct interpretation is:
- P(Y< 16) = 0.041. About 4.1% of all toco toucans weigh less than 16 ounces
A similar problem is given at brainly.com/question/24663213
There are 12 face cards and 4 aces to choose from. For the first card, the probability of drawing a face is

. Then the probability of drawing an ace second is

.
So the probability of drawing these two particular cards in the given order is
Step-by-step explanation:
Given expression is x⁴-kx²+4 =0
x−2 is a factor of the given expression.
So, x=2
Substitute in the equation, we get
2⁴-k(2)²+4
⇒16+4k+4=0
⇒4k=−20
⇒k=−5
Answer:
1. 3
2. 2
Step-by-step explanation:
| |
x | + | 1 | | x^2 | + | 4 x | - | 2
x^3 | + | 5 x^2 | + | 2 x | + | 1
x^3 | + | x^2 | | | |
| | 4 x^2 | + | 2 x | |
| | 4 x^2 | + | 4 x | |
| | | | -2 x | + | 1
| | | | -2 x | - | 2
| | | | | | 3
__________________________________________
| |
x | - | 5 | | x^2 | - | x | + | 0
x^3 | - | 6 x^2 | + | 5 x | + | 2
x^3 | - | 5 x^2 | | | |
| | -x^2 | + | 5 x | |
| | -x^2 | + | 5 x | |
| | | | | | 2
| | | | | | 0
| | | | | | 2