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vova2212 [387]
3 years ago
10

A relationship between two variables is described below. We can think of one variable as helping to explain the other. Is the in

dicated variable the explanatory variable or the response variable? Lung capacity and number of years smoking cigarettes. Number of years smoking cigarettes is the:
Mathematics
1 answer:
kramer3 years ago
3 0

Answer:

Explanatory Variable

Step-by-step explanation:

The variable that we can change is called the Explanatory variable.

The response variable dependent upon the explanatory variable, as we change the value of the explanatory variable the value of the response variable is also gets changed.

The number of years smoking a cigarette is in our control so it is an explanatory variable.

and, the impact of the number of years smoking a cigarette is directly on lung capacity, so it is Response variable.

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makvit [3.9K]

Answer:

3.159 is answer for the solution

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3 years ago
What is the area of a sector with a central angle of 2π/9 radians and a radius of 16.7 ft?
Y_Kistochka [10]

Answer:

Area of the sector is 97.30 square feet.

Step-by-step explanation:

The area of the sector is given by

A=(\frac{\theta}{2})r^2

Plugging the known values in this formula to find the area of the sector

A=(\frac{2\pi/9}{2})(16.7)^2\\\\A=\frac{2\pi}{18}\cdot16.7^2

Use the value of π as 3.14

A=\frac{2\cdot3.14}{18}\cdot16.7^2

Simplifying, we get

A=97.3016

Rounded to the nearest hundredth, we get

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8 0
3 years ago
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Somebody help me.....
Elan Coil [88]

Answer:

in my knowledge

26 , 31 , 36 , 41 , 46

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8 0
3 years ago
Please help! the answer is in fraction form
vlada-n [284]

Answer:

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Step-by-step explanation:

4 0
3 years ago
Find the area under the curve y = 13/x3 from x = 1 to x = t. Evaluate the area under the curve for t = 10, t = 100, and t = 1000
zvonat [6]

Answer:

t = 10

A = 32496.75

t = 100

A = 324999996.8

t = 1000

A=3.25\times 10^{12}

Step-by-step explanation:

The area under the curve is calculated by using the following definite integral:

A = \int\limits^t_ {1} \,{13\cdot x^{3}}  dx

A = 13 \int\limits^t_1 {x^{3}} \, dx

A = \frac{13}{4}\cdot (t^{4}-1)

Evaluated areas are presented below:

t = 10

A = 32496.75

t = 100

A = 324999996.8

t = 1000

A=3.25\times 10^{12}

8 0
3 years ago
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