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3 years ago

Geometry. Find the angle

Mathematics

2 answers:

lisabon 2012 [21]3 years ago

7 0

Answer:

x = 10°; Angle A = 84°

Step-by-step explanation:

Angle A + Angle B = 180

5x + 34 + 2x + 76 = 180

7x + 110 = 180

7x = 70

x = 10

Angle A: 5(10) + 34 = 50 + 34 = 84°

Vikki [24]3 years ago

7 0

Answer:

Step-by-step explanation:

Because the two lines are parallel, the angles are supplementary. This means they will add up to 180 degrees.

So all you have to do is add the measures of the two angles to get 180.

<u>5x+34</u>+<u>2x+76</u>=180

(simplify)

7x+110=180

7x=70

x=10

Now all you have to do is plug this into the equation for <A

5(10)+34=?

50+34=?

84=84

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3 years ago

A rectangular filed is 190m by 270m . A rectangular barn is 23 m by 40 m is built in the field .

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Answer: 50,380m

Step-by-step explanation:

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3 years ago

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Molodets [167]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Ancient paintings were found on cave walls in South America. The Carbon-14 in the paintings was measured and was found to be 19%

balu736 [363]

Answer: C. 13,839 (the answer is not among the given options, however the result is near this value)

Step-by-step explanation:

The exponential decay model for Carbon- 14 is given by the followig formula:

$A=A_{o}e^{-0.0001211.t}$ (1)

Where:

$A$ is the final amount of Carbon- 14

$A_{o}=$ is the initial amount of Carbon- 14

$t$ is the time elapsed (the value we want to find)

On the other hand, we are told the current amount of Carbon-14 $A$ is $19\%=0.19$ , assuming the initial amount of Carbon-14 $A_{o}=$ is $100\%$ :

$A=0.19A_{o}$ (2)

This means: $\frac{A}{A_{o}}=0.19$ (2)

Now,finding $t$ from (1):

$\frac{A}{A_{o}}=e^{-0.0001211.t}$ (3)

Applying natural logarithm on both sides:

$ln(\frac{A}{A_{o}})=ln(e^{-0.0001211.t})$ (4)

$ln(0.19)=-0.0001211.t$ (5)

$t=\frac{ln(0.19)}{-0.0001211}$ (6)

Finally:

$t=13713.717years$ This is the age of the paintings and the option that is nearest to this value is C. 13839 years

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2 years ago

E(5,3) and F (2,-1) are two vertices of a square EFGH and H is in the x-axis .Find the coordinates of H and G. Please need answe

timurjin [86]

Answer:

coordinates of H = (1, 0)

Coordinates of G = ( - 3.6, -2) or (5.6, -2)

Step-by-step explanation:

E(5,3) and F (2,-1) are two vertices of a square EFGH and H is in the x-axis.

Let the coordinates of H is (x, 0) and G is (a, b).

The length of side EF is

$EF = \sqrt{(5 -2)^2 + (3 +1)^2} = 5$

So,

$EH = \sqrt{(5 -x)^2 + (3 -0)^2} = 5\\\\(5 -x)^2+ 9 = 25\\\\5 - x = 4\\\\x = 1$

And

$GH = \sqrt{(a -x)^2+ b^2} = 5\\\\(a -1)^2+ b^2 = 25\\\\a^2 + b^2 + 1 - 2 a = 25\\\\a^2 + b^2 - 2a = 24 .... (1)$

Now

$FG = \sqrt{(a -2)^2+ (b +1)^2} = 5\\\\(a -2)^2+ (b+1)^2 = 25\\\\a^2 + b^2 + 2b - 2 a = 20\\ ..... (2)$

Solving (1) and (2)

b = - 2 ,

$a = \frac{2 \pm\sqrt{4 + 80}}{2}\\\\a = \frac{2 \pm 9.2}{2}\\\\a = - 3.6, 5.6$

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