5c+10=40.................

Mathematics

2 answers:

jeka943 years ago

6 0

Answer

c=6

Step-by-step explanation:

subtract both sides by ten

c+10-10=40-10

5c=30

divide both sides by 5

5c/5=3-/5

ANTONII [103]3 years ago

3 0

C = 6

Image provided.

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What are the coordinates of the intersection of the diagonals of parallelogram LMNO, with vertices L(0,-3), M(-2,1), N(1,5), O(3

ArbitrLikvidat [17]

ANSWER

$\boxed {( \frac{1}{2} , 1)}$

EXPLANATION

The given parallelogram has vertices,

L(0,-3), M(-2,1), N(1,5), O(3,1).

The diagonals of the parallelogram bisect each other.

From the diagram, we can see that, the diagonals have coordinates L(0,-3),N(1,5)

and

M(-2,1),O(3,1).

The midpoint of any of the diagonals will give us the coordinates of intersection of the diagonals.

Recall the midpoint formula,

$(\frac{x_1+x_2}{2}, \frac{y_2+y_1}{2})$

Using L(0,-3),N(1,5) gives,

$(\frac{0+1}{2}, \frac{ - 3+5}{2})$

$(\frac{1}{2}, \frac{ 2}{2})$

$(\frac{1}{2}, 1)$

Or we could have also used,M(-2,1),O(3,1) to get,

$(\frac{-2+3}{2}, \frac{ 1+1}{2})$

$(\frac{ 1}{2}, \frac{ 2}{2})$

$(\frac{ 1}{2}, 1)$

The correct answer is C