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2 years ago

16 squared with explanation.

Mathematics

2 answers:

pochemuha2 years ago

7 0

Answer:

256

Step-by-step explanation:

Multiply 16 by 16.

You bet 256, right?

The answer is 256 now.

Hope it helps!

Formula: multiply number you have x number you have.

julsineya [31]2 years ago

7 0

Answer:

256

Step-by-step explanation:

answer is 256

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, list the first five terms of each sequence, and identify them as arithmetic or geometric.

Scrat [10]

Each element is 2/3 times the previous one, so that's a geometric sequence.

6×(2/3)=4, 4×(2/3)=8/3, 8/3×(2/3)=16/9, 16/9×(2/3)=32/27

Answer: 6, 4, 8/3, 16/9, 32/27

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2 years ago

Circle which of the following are

Mice21 [21]

I guess it’s 2.ace and diamond

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2 years ago

Simplify.<br> (WILL GIVE BRAINLIEST)

Novosadov [1.4K]

Answer:

$\frac{\sqrt{x} }{2x}$

Step-by-step explanation:

Rationalize the denominator first (keep in mind we are NOT solving this because there is no equals sign here. We are merely simplifying.)

$\frac{\sqrt{5x} }{x\sqrt{20} } *\frac{\sqrt{20} }{\sqrt{20} } =\frac{\sqrt{100x} }{20x}$

Now simplify by taking the square root of 100 to get:

$\frac{10\sqrt{x} }{20x}$

Divide numerator and denomiator by 10 to get:

$\frac{\sqrt{x} }{2x}$

4 0

2 years ago

Assume that the flask shown in the diagram can be modeled as a combination of a sphere and a cylinder. Based on this assumption,

kompoz [17]

If the flask shown in the diagram can be modeled as a combination of a sphere and a cylinder, then its volume is

$V_{flask}=V_{sphere}+V_{cylinder}.$

Use following formulas to determine volumes of sphere and cylinder:

$V_{sphere}=\dfrac{4}{3}\pi R^3,\\ \\V_{cylinder}=\pi r^2h,$

wher R is sphere's radius, r - radius of cylinder's base and h - height of cylinder.

Then

$V_{sphere}=\dfrac{4}{3}\pi R^3=\dfrac{4}{3}\pi \left(\dfrac{4.5}{2}\right)^3=\dfrac{4}{3}\pi \left(\dfrac{9}{4}\right)^3=\dfrac{243\pi}{16}\approx 47.71;$
$V_{cylinder}=\pi r^2h=\pi \cdot \left(\dfrac{1}{2}\right)^2\cdot 3=\dfrac{3\pi}{4}\approx 2.36;$
$V_{flask}=V_{sphere}+V_{cylinder}\approx 47.71+2.36=50.07.$

Answer 1: correct choice is C.

If both the sphere and the cylinder are dilated by a scale factor of 2, then all dimensions of the sphere and the cylinder are dilated by a scale factor of 2. So

R'=2R, r'=2r, h'=2h.

Write the new fask volume:

$V_{\text{new flask}}=V_{\text{new sphere}}+V_{\text{new cylinder}}=\dfrac{4}{3}\pi R'^3+\pi r'^2h'=\dfrac{4}{3}\pi (2R)^3+\pi (2r)^2\cdot 2h=\dfrac{4}{3}\pi 8R^3+\pi \cdot 4r^2\cdot 2h=8\left(\dfrac{4}{3}\pi R^3+\pi r^2h\right)=8V_{flask}.$