Apply the Pyth Thm twice:
diagonal of base is sqrt(4^2+6^2).
Then the length of diagonal AB is L = [sqrt(4^2+6^2)]^2 + [sqrt(1)]^2
Answer:
y = 1/3
Step-by-step explanation:
2/3 (6y - 4) = - 4y
2(6y-4)/3 = -4y
2(6y-4) = (-3)(4y)
y = 1/3
Answer:
the ability to objectively analyze information and draw a rational conclusion
Step-by-step explanation: