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3 years ago

What equation is described below?

Mathematics

2 answers:

iragen [17]3 years ago

5 0

Answer:

5×11=55

Step-by-step explanation:

if 55= 5× as many as 11

55=5×11

ik it doesn't make sense:(

Zolol [24]3 years ago

3 0

The answer is 5x11=55

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Solve the following equation for D. Be sure to take into account whether a letter is capitalized or not. fD - 7 = q^2

Alecsey [184]

Answer:

$\displaystyle D=\frac{q^2+7}{f}$

Step-by-step explanation:

<u>Equation Solving</u>

We are given the equation:

$fD - 7 = q^2$

It's required to solve the equation for D. All letters must preserve their capitalization.

We must isolate the letter D by removing from the left side all the terms and coefficients that surround it.

Adding 7:

$fD = q^2+7$

Dividing by f:

$\mathbf{\displaystyle D=\frac{q^2+7}{f}}$

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2 years ago

What is the coordinate (10,2) multiplied by two fifths equal

Ronch [10]

I think it's (4,4/5).

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3 years ago

A. -4m - 12 - 5m = 13

vladimir2022 [97]

Answer:

Hope this helps!

Step-by-step explanation:

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3 years ago

If a | | b and c | | d , which pair of angles are congruent?

Delicious77 [7]

Answer:

What are the relative frequencies, to the nearest hundredth, of the rows of the two-way table?

A B

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Group 2 20 25

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Ashley, Bob, Claire, and Daniel are among 13 students who entered a lottery to win a free vacation to Paris.

AlladinOne [14]

Answer:

0.0014 = 0.14% probability that Ashley, Bob, Claire, and Daniel will be chosen.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the students are chosen is not important, so the combinations formula is used to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Desired outcomes:

4 students from a set of 4(Ashley, Bob, Claire, and Daniel). So

$D = C_{4,4} = \frac{4!}{4!(4-4)!} = 1$

Total outcomes:

4 students from a set of 13(number of students in the lottery). So

$T = C_{13,4} = \frac{13!}{4!(13-4)!} = 715$

Probability:

$p = \frac{D}{T} = \frac{1}{715} = 0.0014$

0.0014 = 0.14% probability that Ashley, Bob, Claire, and Daniel will be chosen.

7 0

3 years ago