2 years ago

Solve this inequality. 4n-3<=21

Mathematics

1 answer:

icang [17]2 years ago

5 0

The answer Will be: n<=6

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Answer:

in step 4

Step-by-step explanation:

we have

$0.5(-12c+6)-3(c+4)+10(c-5)\\\\step1=-12c(0.5)+6(0.5)-3(c+4)+10(c-5)\\\\=-6c+3-3(c+4)+10(c-5)\\\\$

so step 1 is correct

step 2

$-6c+3-3(c+4)+10(c-5)\\\\=-6c+3+c(-3)+4(-3)+10(c-5)\\\\=-6c+3-3c-12+10(c-5)$

so step 2 is correct

step 3

$-6c+3-3c-12+10(c-5)\\\\=-6c+3-3c-12+c(10)-5(10)\\\\=-6c+3-3c-12+10c-50$

so step 3 is correct

step 4

$-6c+3-3c-12+10c-50\\\\=(-6c-3c+10c)+(3-12-50)\\\\=(-6-3+10)c+(-9-50)\\\\=(-9+10)c-59\\\\=c-59$

so step 4 is incorrect

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Step-by-step explanation:

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2 years ago

Solve this inequality.​ 4n-3<=21

Solve this inequality. 4n-3<=21