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3 years ago

12

Write a problem that can be solved with a bar model that shows equal groups of liters

1 answer:

ioda3 years ago

8 0

"In Grade 2 and early in Grade 3, students learned to use bar models to solve two-step problems involving addition and subtraction. This is extended in this chapter to include multiplication and division.

<span>Both multiplication and division are based on the concept of equal groups, or the part-part-whole concept, where each equal group is one part of the whole. In Grade 2, students showed this with one long bar (the whole) divided up into equal-sized parts, or units. This unitary bar model represents situations such as basket of apples being grouped equally into bags." </span>https://www.sophia.org/tutorials/math-in-focus-chapter-9-bar-modeling-with-multipli

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Calculate the length of side AC:

lisabon 2012 [21]

Answer:

146⁰ + x = 180

x = 34⁰ is AC ..a..a.

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2 years ago

WHO DOESN'T LOVE MAX POINTS. MAX POINT QUESTION<br> PLS ANSWER THIS TRIGONOMETRY QUESTION

mezya [45]

Answer:

Solution given:

opposite:9

adjacent: 12

$\theta=?$

Relationship between opposite and adjacent is given by tan angle

so

$Tan \theta=\frac{opposite} {adjacent}=\frac{9}{12}$

$Tan \theta=\frac{3}{4}$

$\theta=Tan^{-1}\frac{3}{4}$

$\bold{\theta=36.8°}$

#11.

hypotenuse[h]=11cm

opposite/perpendicular[P]=b cm

adjacent/base[b]=a cm

now

$\theta=62°$

Relationship between height and hypotenuse is given by Sin angle

:.

Sin 62°= $\frac{opposite}{hypotenuse}=\frac{b}{11}$

doing crisscrossed multiplication

b=Sin 62°*11

:.b=9.71 cm

a) At <u>9</u><u>.</u><u>7</u><u>1</u><u> </u>cm height does the ladder touch the building.

again

Relationship between base and hypotenuse is given by Cos angle

:.Cos 62°= $\frac{base}{hypotenuse}=\frac{a}{11}$

doing crisscrossed multiplication

a=Cos 62°×11

a=5.16cm

b) the distance between the foot of the ladder and the building is <u>5.16cm.</u>

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2 years ago

X and Y are independent random variables. X is normally distributed with mean 1 and variance 1. Y is normally distributed with m

g100num [7]

Answer:

1

Step-by-step explanation:

Equation of variance:

Total Variance = sum (i=1, N) {c^2,variance^2}

= c1^2*variance1^2 + c2^2*variance2^2 + .....

Variance of X = 1

Variance of Y = 5

Variance of Y - 2X = (1^2)*(5) - (2^2)**(1)

= 5 - 4 = 1

8 0

3 years ago

76 divided 19 using an array

Sav [38]

It’s 4, I hope it helps!!

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2 years ago

Read 2 more answers

What is the x intercept of y + 4 =− 4(x − 1)

vivado [14]

Answer:

0

Step-by-step explanation:

since the "b" in y=mx+b ends up being 0, that means that the y intercept is 0, which also means that the x intercept is 0.

7 0

2 years ago