Rewrite the expression in the form y^n<br> (y^4)^2

The residents of a city voted on whether to raise property taxes. The ratio of yes votes to no votes was 7 to 4. If there were 4

Elena-2011 [213]

Answer:

2628

Step-by-step explanation:

7/4 = 1.75 = 175%

x is the number of no votes

4599/x = 7/4

x = 4599/(7/4)

x = 2628

5 0

2 years ago

A problem states: "There are 2 more horses than cows in a field. There are 15 animals in the field in all. How many horses are t

mash [69]

Let h = the number of horses in the field
Let c = number of cows in the field

There are 2 more horses than cows in the field. Therefore
h = c + 2
or
c = h - 2 (1)

There are 15 animals in the field. Therefore
h + c = 15 (2)

Substitute (1) into (2).
h + (h - 2) = 15
2h - 2 = 15

Answer:
The correct equation is
2h - 2 = 15

4 0

3 years ago

Read 2 more answers

Of 24 employees at a local supermarket, 13 work as cashiers and 11 stock shelves. If 4 employees are selected at random to work

kenny6666 [7]

Answer:

The required probability is, $\simeq 0.06729$

Step-by-step explanation:

Of 24 employees at a local supermarket, 13 work as cashiers and 11 stock shelves. If 4 employees are selected at random to work overtime, then

P( all 4 are cashiers) = $\frac{^{13}{C}_{4}}{^{24}{C}_{4}}$

$\simeq 0.06729$

4 0

3 years ago

Read 2 more answers

I need a real answer to this problem and if you can't answer then please don't answer this. Just give me the answer for the blan

Harlamova29_29 [7]

To divide the triangles into these regions, you should construct the <u>perpendicular bisector</u> of each segment.
These perpendicular bisectors intersect and divide each triangle into three regions.
The points in each region are those closest to the vertex in that <u>region</u>.

<h3>What is a triangle?</h3>

A triangle can be defined as a two-dimensional geometric shape that comprises three (3) sides, three (3) vertices and three (3) angles only.

<h3>What is a line segment?</h3>

A line segment can be defined as the part of a line in a geometric figure such as a triangle, circle, quadrilateral, etc., that is bounded by two (2) distinct points and it typically has a fixed length.

<h3>What is a perpendicular bisector?</h3>

A perpendicular bisector can be defined as a type of line that bisects (divides) a line segment exactly into two (2) halves and forms an angle of 90 degrees at the point of intersection.

In this scenario, we can reasonably infer that to divide the triangles into these regions, you should construct the <u>perpendicular bisector</u> of each segment. These perpendicular bisectors intersect and divide each triangle into three regions. The points in each region are those closest to the vertex in that <u>region</u>.

Read more on perpendicular bisectors here: brainly.com/question/27948960

#SPJ1

5 0

2 years ago

Assume that you have a sample of n 1 equals 6, with the sample mean Upper X overbar 1 equals 50, and a sample standard deviati

tigry1 [53]

Answer:

$t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656$

$df=6+5-2=9$

$p_v =P(t_{9}>2.656) =0.0131$

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

Step-by-step explanation:

Data given

$n_1 =6$ represent the sample size for group 1

$n_2 =5$ represent the sample size for group 2

$\bar X_1 =50$ represent the sample mean for the group 1

$\bar X_2 =38$ represent the sample mean for the group 2

$s_1=7$ represent the sample standard deviation for group 1

$s_2=8$ represent the sample standard deviation for group 2

System of hypothesis

The system of hypothesis on this case are:

Null hypothesis: $\mu_1 \leq \mu_2$

Alternative hypothesis: $\mu_1 > \mu_2$

We are assuming that the population variances for each group are the same

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

The statistic for this case is given by:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

The pooled variance is:

$S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

We can find the pooled variance:

$S^2_p =\frac{(6-1)(7)^2 +(5 -1)(8)^2}{6 +5 -2}=55.67$

And the pooled deviation is:

$S_p=7.46$

The statistic is given by:

$t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656$

The degrees of freedom are given by:

$df=6+5-2=9$

The p value is given by:

$p_v =P(t_{9}>2.656) =0.0131$

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

4 0

3 years ago

Rewrite the expression in the form y^n (y^4)^2