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3 years ago

Suppose that you have $11 comma 000

Mathematics

1 answer:

Vlada [557]3 years ago

5 0

Answer:

The financial advisor is not using percentage properly.

Percentage loss=2%

Step-by-step explanation:

original amount invested=$11000

By the end of the first year, there was a decrease by 30% over the original amount.

This implies that the amount invested at after the end of the first year or at the beginning of the second year

$= \frac{70}{100} \times 11000$

=$7,700

This amount has increased by 40%

$= \frac{140}{100} \times7700$

=$10,780

The financial advisor is not using percentage properly.

This is because the decrease was on the original amount meanwhile the increase was not on the original amount. The increase was rather on an amount less than the original amount .

Since the original amount invested is greater than the amount at the end of the second year, there was a loss

Hence percentage loss

$=\frac{11000 - 10780}{1100} \times 100\%$

$\frac{220}{11000}\times100\% = 2\%$

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Help me please i need some help.

Ber [7]

Answer:

2,5, 6

Step-by-step explanation:

a coefficient is the number placed before the variable in equations and the other numbers, in this case 7 and 4, are called constants

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3 years ago

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DENIUS [597]

Answer:

a) 30

b) 88

c) 70

d) 16

e) 160

f) 250

Step-by-step explanation:

So the first step would be to switch the numbers around. For example A would be 15 and 50 instead of the original order of 50 and 15. You would then take the 1st number in the new arranged order (15) and multiply it by 100, then divide in that order. 1500/50 = 30.

Another example, letter B.

Step 1 - Rearrange : 22 and 25

Step 2 - Multiple by 100 = 2200

Step 3 - Divide : 2200/25 = 88

Good Luck :) Hope this helped.

5 0

2 years ago

3. For the polynomial: ()=−2(+19)3(−14)(+3)2, do the following:A. Create a table of values that have the x-intercepts of p(x) in

Pepsi [2]

Part A. We are given the following polynomial:

$\mleft(\mright)=-2\mleft(+19\mright)^3\mleft(-14\mright)\mleft(+3\mright)^2$

This is a polynomial of the form:

$p=k(x-a)^b(x-c)^d\ldots(x-e)^f$

The x-intercepts are the numbers that make the polynomial zero, that is:

$\begin{gathered} p=0 \\ (x-a)^b(x-c)^d\ldots(x-e)^f=0 \end{gathered}$

The values of x are then found by setting each factor to zero:

$\begin{gathered} (x-a)=0 \\ (x-c)=0 \\ \text{.} \\ \text{.} \\ (x-e)=0 \end{gathered}$

Therefore, this values are:

$\begin{gathered} x=a \\ x=c \\ \text{.} \\ \text{.} \\ x=e \end{gathered}$

In this case, the x-intercepts are:

$\begin{gathered} x=-19 \\ x=14 \\ x=-3 \end{gathered}$

The multiplicity are the exponents of the factor where we got the x-intercept, therefore, the multiplicities are:

Part B. The degree of a polynomial is the sum of its multiplicities, therefore, the degree in this case is:

$\begin{gathered} n=3+1+2 \\ n=6 \end{gathered}$

To determine the end behavior of the polynomial we need to know the sign of the leading coefficient that is, the sign of the coefficient of the term with the highest power. In this case, the leading coefficient is -2, since the degree of the polynomial is an even number this means that both ends are down. If the leading coefficient were a positive number then both ends would go up. In the case that the leading coefficient was positive and the degree and odd number then the left end would be down and the right end would be up, and if the leading coefficient were a negative number and the degree an odd number then the left end would be up and the right end would be down.

Part C. A sketch of the graph is the following:

If the multiplicity is an odd number the graph will cross the x-axis at that x-intercept and if the multiplicity is an even number it will tangent to the x-axis at that x-intercept.

6 0

2 years ago

HELP PLEASE PLEASE I WILL GIVE BRAINLIEST

podryga [215]

In the top the "f(x)" equals 9, now they are asking you to add onto the 9 by 1 causing it to be 10. If you did the first few you would have noticed that it takes 9 in order to get to 5 from -4.

here are the answers btw:

8 0

3 years ago

A bee flies 20 feet per second directly to a flowerbed from its hive. The bee stays at the flowerbed for fifteen minutes. Then i

Ksenya-84 [330]

A. The equation to find the distance of the flowerbed from the hive is: $\frac{x}{20}+\frac{x}{12}+900= 1200$ , where x is the distance.

B. The flowerbed is 2250 feet far from the hive.

<u><em>Explanation</em></u>

Suppose, the distance of the flowerbed from the hive is $x$ feet.

The bee flies 20 feet per second directly to a flowerbed from its hive and flies directly back to the hive at 12 feet per second.

As, $Time=\frac{Distance}{Speed}$

So, the time taken by the bee to reach the flowerbed $= \frac{x}{20}$ seconds and the time taken to fly back to the hive $=\frac{x}{12}$ seconds.

The bee stays at the flowerbed for 15 minutes or (15×60)seconds or 900 seconds and it is away from the hive for a total of 20 minutes or (20×60)seconds or 1200 seconds.

So, the equation will be.......

$\frac{x}{20}+\frac{x}{12}+900= 1200\\ \\ \frac{3x+5x}{60}= 300\\ \\ 8x= 60*300\\ \\ 8x=18000\\ \\ x=\frac{18000}{8}=2250$

Thus, the distance of the flowerbed from the hive is 2250 feet.

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4 years ago

Suppose that you have ​$11 comma 000

Suppose that you have $11 comma 000